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The point from which the tangents to the circles x2 + y2 – 8x + 40 = 0,  5x2 + 5y2 – 25 x + 80 = 0, x2 + y2 – 8x + 16y + 160 = 0 are equal in length is
  • a)
  • b)
  • c)
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
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The point from which the tangents to the circles x2+ y2–8x + 40 ...
The Required point is the radical centre of the three given circles. The radical axes of the three circles taken in pairs are 3x - 24 = 0,16y + 120 = 0 and - 3x + 16y + 80 = 0. On solving, the required point is (8, -15/2).
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The point from which the tangents to the circles x2+ y2–8x + 40 ...
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The point from which the tangents to the circles x2+ y2–8x + 40 = 0,5x2+ 5y2–25 x + 80 = 0, x2+ y2–8x + 16y + 160 = 0 are equal in length isa)b)c)d)None of theseCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The point from which the tangents to the circles x2+ y2–8x + 40 = 0,5x2+ 5y2–25 x + 80 = 0, x2+ y2–8x + 16y + 160 = 0 are equal in length isa)b)c)d)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The point from which the tangents to the circles x2+ y2–8x + 40 = 0,5x2+ 5y2–25 x + 80 = 0, x2+ y2–8x + 16y + 160 = 0 are equal in length isa)b)c)d)None of theseCorrect answer is option 'C'. Can you explain this answer?.
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