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Moist air enters the cooling coil with mass flow rate of 10 kg-da/s at dry bulb temperature of 30°C and humidity ratio of 0.017 kg v/da. It leaves the cooling coil at dry bulb temperature of 16°C and humidity ratio of 0.008 kg v/da. If specific heat of humid air is 1.02 kJ/kg da K and latent heat of water vapour is 2500 kJ/kg v. The sensible and latent heat transfer of cooling coil are, respectively
  • a)
    140 kW and 25000 kW
  • b)
    142.8 kW and 2.25 kW
  • c)
    142.8 kW and 225 kW
  • d)
    225 kW and 142.8 kW
Correct answer is option 'C'. Can you explain this answer?
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Moist air enters the cooling coil with mass flow rate of 10 kg-da/s at...
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Moist air enters the cooling coil with mass flow rate of 10 kg-da/s at...
Given data:
- Mass flow rate of moist air (ṁ): 10 kg-da/s
- Inlet conditions:
- Dry bulb temperature (T1): 30°C
- Humidity ratio (W1): 0.017 kg v/da
- Outlet conditions:
- Dry bulb temperature (T2): 16°C
- Humidity ratio (W2): 0.008 kg v/da
- Specific heat of humid air (Cp): 1.02 kJ/kg da K
- Latent heat of water vapor (Lv): 2500 kJ/kg v

To find:
- Sensible heat transfer (Qs)
- Latent heat transfer (Ql)

Calculation:

1. Sensible Heat Transfer (Qs):
The formula to calculate sensible heat transfer is:
Qs = ṁ * Cp * (T1 - T2)

Substituting the given values:
Qs = 10 * 1.02 * (30 - 16)
Qs = 10 * 1.02 * 14
Qs = 142.8 kW

2. Latent Heat Transfer (Ql):
The formula to calculate latent heat transfer is:
Ql = ṁ * (W1 - W2) * Lv

Substituting the given values:
Ql = 10 * (0.017 - 0.008) * 2500
Ql = 10 * 0.009 * 2500
Ql = 225 kW

Therefore, the sensible heat transfer (Qs) is 142.8 kW and the latent heat transfer (Ql) is 225 kW. Hence, the correct answer is option 'C' (142.8 kW and 225 kW).
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Moist air enters the cooling coil with mass flow rate of 10 kg-da/s at dry bulb temperature of 30°C and humidity ratio of 0.017 kg v/da. It leaves the cooling coil at dry bulb temperature of 16°C and humidity ratio of 0.008 kg v/da. If specific heat of humid air is 1.02 kJ/kg da K and latent heat of water vapour is 2500 kJ/kg v. The sensible and latent heat transfer of cooling coil are, respectivelya)140 kW and 25000 kWb)142.8 kW and 2.25 kWc)142.8 kW and 225 kWd)225 kW and 142.8 kWCorrect answer is option 'C'. Can you explain this answer?
Question Description
Moist air enters the cooling coil with mass flow rate of 10 kg-da/s at dry bulb temperature of 30°C and humidity ratio of 0.017 kg v/da. It leaves the cooling coil at dry bulb temperature of 16°C and humidity ratio of 0.008 kg v/da. If specific heat of humid air is 1.02 kJ/kg da K and latent heat of water vapour is 2500 kJ/kg v. The sensible and latent heat transfer of cooling coil are, respectivelya)140 kW and 25000 kWb)142.8 kW and 2.25 kWc)142.8 kW and 225 kWd)225 kW and 142.8 kWCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Moist air enters the cooling coil with mass flow rate of 10 kg-da/s at dry bulb temperature of 30°C and humidity ratio of 0.017 kg v/da. It leaves the cooling coil at dry bulb temperature of 16°C and humidity ratio of 0.008 kg v/da. If specific heat of humid air is 1.02 kJ/kg da K and latent heat of water vapour is 2500 kJ/kg v. The sensible and latent heat transfer of cooling coil are, respectivelya)140 kW and 25000 kWb)142.8 kW and 2.25 kWc)142.8 kW and 225 kWd)225 kW and 142.8 kWCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Moist air enters the cooling coil with mass flow rate of 10 kg-da/s at dry bulb temperature of 30°C and humidity ratio of 0.017 kg v/da. It leaves the cooling coil at dry bulb temperature of 16°C and humidity ratio of 0.008 kg v/da. If specific heat of humid air is 1.02 kJ/kg da K and latent heat of water vapour is 2500 kJ/kg v. The sensible and latent heat transfer of cooling coil are, respectivelya)140 kW and 25000 kWb)142.8 kW and 2.25 kWc)142.8 kW and 225 kWd)225 kW and 142.8 kWCorrect answer is option 'C'. Can you explain this answer?.
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