A slow FH binary FSK system with non coherent detection operates at ...
Explanation:
To determine the bandwidth occupancy for worst-case jamming in a slow FH binary FSK system with non-coherent detection, we need to consider the hopping bandwidth and the bit rate of the system.
Hopping Bandwidth:
Given that the hopping bandwidth is 2 GHz, this means that the frequency of each hop in the FH system can vary by up to 2 GHz. The system uses frequency shift keying (FSK), which means that it can have two different frequencies for each symbol. Therefore, the frequency spacing between the two frequencies used in the system is given by half of the hopping bandwidth.
Frequency spacing = Hopping bandwidth / 2
Frequency spacing = 2 GHz / 2
Frequency spacing = 1 GHz
Bit Rate:
The bit rate of the system is given as 10 kbps, which means that the system transmits 10,000 bits per second.
Worst-Case Jamming:
In the worst-case scenario, the jammer operates as a partial band jammer. This means that the jammer can occupy a portion of the bandwidth, causing interference in the system.
To determine the bandwidth occupancy for worst-case jamming, we need to consider the maximum number of hops that can be jammed simultaneously. This can be calculated by dividing the bit rate by the frequency spacing.
Maximum number of hops jammed = Bit rate / Frequency spacing
Maximum number of hops jammed = 10,000 / 1 GHz
Maximum number of hops jammed = 10
Since each hop in the FH system can vary by up to 2 GHz, and in the worst-case scenario, 10 hops can be jammed simultaneously, the bandwidth occupancy for worst-case jamming is given by:
Bandwidth occupancy = Frequency spacing * Maximum number of hops jammed
Bandwidth occupancy = 1 GHz * 10
Bandwidth occupancy = 10 GHz
However, the hopping bandwidth of the system is only 2 GHz. Therefore, the actual bandwidth occupancy for worst-case jamming cannot exceed the hopping bandwidth.
Therefore, the correct answer is option 'A', 0.4 GHz.