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 The step involved in POP operation is
  • a)
    decrement stack by 2 and store 8-bit content to address pointed to by SP
  • b)
    store 16-bit content to address pointed to by SP and decrement stack by 1
  • c)
    decrement stack by 1 and store content of top of stack to address pointed to by SP
  • d)
    store content of top of stack to address pointed to by SP and then decrement stack by 1
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The step involved in POP operation isa)decrement stack by 2 and store ...
The POP instruction follows two steps.
1. Store the contents of top of stack pointed to by SP register to the 8-bit memory specified in the instruction.
2. Decrement stack by 1.
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Most Upvoted Answer
The step involved in POP operation isa)decrement stack by 2 and store ...
Explanation:

The POP (Pop the top of the stack) operation is used to remove the topmost element from the stack and store it in memory. The correct step involved in the POP operation is option 'D', which states: "store content of top of stack to address pointed to by SP and then decrement stack by 1."

Let's break down the steps involved in the POP operation:

1. Store content of top of stack: The first step is to retrieve the value from the top of the stack. This value represents the data that was last pushed onto the stack. It is necessary to store this value in memory before it is removed from the stack.

2. Address pointed to by SP: The stack pointer (SP) is a register that points to the top of the stack. The address pointed to by SP represents the memory location where the topmost element of the stack is stored. This address is used to store the value retrieved from the stack.

3. Decrement stack by 1: After storing the topmost element in memory, the stack pointer is decremented by 1 to point to the new top of the stack. This is because the topmost element has been removed, and the next element in the stack becomes the new top.

By following these steps, the POP operation successfully removes the topmost element from the stack and stores it in memory.

It is important to note that the other options mentioned in the question are incorrect:

- Option 'A' is incorrect because it mentions decrementing the stack by 2, which would skip over an element in the stack.
- Option 'B' is incorrect because it mentions storing a 16-bit content, but in a POP operation, typically only the topmost element is removed and stored.
- Option 'C' is incorrect because it mentions decrementing the stack by 1 after storing the content, which would remove the wrong element from the stack.
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The step involved in POP operation isa)decrement stack by 2 and store 8-bit content to address pointed to by SPb)store 16-bit content to address pointed to by SP and decrement stack by 1c)decrement stack by 1 and store content of top of stack to address pointed to by SPd)store content of top of stack to address pointed to by SP and then decrement stack by 1Correct answer is option 'D'. Can you explain this answer?
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