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A clutch plate consists of a pair of contacting surfaces. The inner & outer diameter of the friction disks are 150 mm & 300 mm respectively. The coefficient of friction is 0.25 and the intensity of pressure is 2 MPa. Determine the frictional torque required using the uniform pressure criterion.
  • a)
     3.092 kN-m
  • b)
     58.3 kN-m
  • c)
     2.982 kN-m
  • d)
     13.25 kN-m
Correct answer is option 'A'. Can you explain this answer?
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Solution:

Given data:

Inner diameter of the friction disk (d1) = 150 mm

Outer diameter of the friction disk (d2) = 300 mm

Coefficient of friction (µ) = 0.25

Intensity of pressure (p) = 2 MPa

Frictional torque required (T) = ?

Formula used:

Frictional torque (T) = (π/2) x µ x p x ((d2)^4 - (d1)^4) / ((d2)^3 + (d1)^3)

Calculation:

Substituting the given values in the above formula, we get:

T = (π/2) x 0.25 x 2 x ((300)^4 - (150)^4) / ((300)^3 + (150)^3)

T = 3.092 kN-m

Therefore, the frictional torque required using the uniform pressure criterion is 3.092 kN-m.

Answer: (a) 3.092 kN-m.
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