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The standard e.m.f. of a cell, involving one electron change is found to be 0.591 Vat 25. The equilibrium constant of the reaction is-(F=96500 C mol-1,R=8.314 JK-1mol-1a)1.0×101b)1.0×105c)1.0×1010d)1.0×1030Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The standard e.m.f. of a cell, involving one electron change is found to be 0.591 Vat 25. The equilibrium constant of the reaction is-(F=96500 C mol-1,R=8.314 JK-1mol-1a)1.0×101b)1.0×105c)1.0×1010d)1.0×1030Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard e.m.f. of a cell, involving one electron change is found to be 0.591 Vat 25. The equilibrium constant of the reaction is-(F=96500 C mol-1,R=8.314 JK-1mol-1a)1.0×101b)1.0×105c)1.0×1010d)1.0×1030Correct answer is option 'C'. Can you explain this answer?.

Solutions for The standard e.m.f. of a cell, involving one electron change is found to be 0.591 Vat 25. The equilibrium constant of the reaction is-(F=96500 C mol-1,R=8.314 JK-1mol-1a)1.0×101b)1.0×105c)1.0×1010d)1.0×1030Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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