Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Questions  >  A sinusoid massage signal m(t) is transmitted... Start Learning for Free
A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will be
  • a)
    8
  • b)
    10
  • c)
    12
  • d)
    14
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A sinusoid massage signal m(t) is transmitted by binary PCM without co...
This question is part of UPSC exam. View all Electronics and Communication Engineering (ECE) courses
Most Upvoted Answer
A sinusoid massage signal m(t) is transmitted by binary PCM without co...
Signal-to-Quantization-Noise Ratio (SQNR)

The Signal-to-Quantization-Noise Ratio (SQNR) is a measure of the quality of a digital signal after quantization. It indicates the ratio of the power of the signal to the power of the quantization noise. A higher SQNR value indicates better signal quality.

PCM Encoding

In Pulse Code Modulation (PCM), an analog signal is sampled, quantized, and encoded into a digital signal. The analog signal is sampled at regular intervals, and each sample is assigned a digital value based on its amplitude. The number of bits used to represent each sample determines the resolution and the quality of the digital signal.

Finding the Minimum Number of Bits per Sample

To find the minimum number of bits per sample required to achieve a certain SQNR, we can use the following formula:

SQNR (in dB) = 6.02 * N + 1.76

Where N is the number of bits per sample.

In this case, the required SQNR is at least 48 dB. Plugging this value into the formula, we can solve for N:

48 = 6.02 * N + 1.76
46.24 = 6.02 * N
N ≈ 7.68

Since the number of bits per sample must be an integer, we round up to the nearest whole number, which is 8.

Therefore, the minimum number of bits per sample required to achieve a SQNR of at least 48 dB is 8.

Answer

The correct answer is option 'A' (8 bits).
Attention Electronics and Communication Engineering (ECE) Students!
To make sure you are not studying endlessly, EduRev has designed Electronics and Communication Engineering (ECE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electronics and Communication Engineering (ECE).
Explore Courses for Electronics and Communication Engineering (ECE) exam

Top Courses for Electronics and Communication Engineering (ECE)

A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer?
Question Description
A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer?.
Solutions for A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE). Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A sinusoid massage signal m(t) is transmitted by binary PCM without compression. If the signalto-quantization-noise ratio is required to be at least 48dB, the minimum number of bits per sample will bea)8b)10c)12d)14Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
Explore Courses for Electronics and Communication Engineering (ECE) exam

Top Courses for Electronics and Communication Engineering (ECE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev