A singly charged positive ion is accelerated through a potential diffe...
Mass No. = No. of
p + No. of neutron
= 2.75 × 10
2A = 275
The correct answer is: 275
View all questions of this test
A singly charged positive ion is accelerated through a potential diffe...
Given information:
Potential difference (V) = 1000 V
Magnetic field (B) = 1500 Gauss = 0.15 Tesla
Radius of circular path (r) = 0.122 m
To find:
Mass number of the ion
Formula used:
The equation for the radius of the circular path of a charged particle moving in a magnetic field is given by:
r = mv / (qB)
where,
r = radius of the circular path
m = mass of the ion
v = velocity of the ion
q = charge of the ion
B = magnetic field
Solving for mass number:
Since the charge of the ion is singly charged (q = 1), we can rewrite the equation as:
r = mv / (B)
We know that the potential difference is given by:
V = qV
where,
V = potential difference
q = charge of the ion
So, we can rewrite the equation as:
V = (1/2)mv^2
Simplifying the equations, we get:
r = (2V / B)^0.5
v = (2V / m)^0.5
To eliminate the velocity (v), we substitute the value of v in terms of r into the equation for r:
r = (2V / mB)^0.5
r^2 = 2V / mB
m = 2V / (r^2B)
Substituting the given values:
m = 2 * 1000 / (0.122^2 * 0.15)
m ≈ 274.96
Since the mass number must be a whole number, we round it to the nearest whole number:
m ≈ 275
Therefore, the mass number of the ion is 275 (option A).