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A singly charged positive ion is accelerated through a potential difference of 1000V in a mass spectrograph. It then passes through a uniform magnetic field B = 1500 Gauss and then deflected into a circular path of radius 0.122 m. The mass number of the ion is :
  • a)
    275 
  • b)
    200 
  • c)
    100 
  • d)
    159 
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A singly charged positive ion is accelerated through a potential diffe...
Mass No. = No. of p + No. of neutron

= 2.75 × 102
A = 275
The correct answer is: 275
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Most Upvoted Answer
A singly charged positive ion is accelerated through a potential diffe...
Given information:
Potential difference (V) = 1000 V
Magnetic field (B) = 1500 Gauss = 0.15 Tesla
Radius of circular path (r) = 0.122 m

To find:
Mass number of the ion

Formula used:
The equation for the radius of the circular path of a charged particle moving in a magnetic field is given by:

r = mv / (qB)

where,
r = radius of the circular path
m = mass of the ion
v = velocity of the ion
q = charge of the ion
B = magnetic field

Solving for mass number:
Since the charge of the ion is singly charged (q = 1), we can rewrite the equation as:

r = mv / (B)

We know that the potential difference is given by:

V = qV

where,
V = potential difference
q = charge of the ion

So, we can rewrite the equation as:

V = (1/2)mv^2

Simplifying the equations, we get:

r = (2V / B)^0.5
v = (2V / m)^0.5

To eliminate the velocity (v), we substitute the value of v in terms of r into the equation for r:

r = (2V / mB)^0.5
r^2 = 2V / mB
m = 2V / (r^2B)

Substituting the given values:

m = 2 * 1000 / (0.122^2 * 0.15)
m ≈ 274.96

Since the mass number must be a whole number, we round it to the nearest whole number:

m ≈ 275

Therefore, the mass number of the ion is 275 (option A).
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A singly charged positive ion is accelerated through a potential difference of 1000Vin a mass spectrograph. It then passes through a uniform magnetic fieldB= 1500 Gauss and then deflected into a circular path of radius 0.122m. The mass number of the ion is :a)275b)200c)100d)159Correct answer is option 'A'. Can you explain this answer?
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