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A singly charged positive ion is accelerated through a potential difference of 1000V in a mass spectrograph. It then passes through a uniform magnetic field B = 1500 Gauss and then deflected into a circular path of radius 0.122 m. The mass number of the ion is :
- a)275
- b)200
- c)100
- d)159
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A singly charged positive ion is accelerated through a potential diffe...
Mass No. = No. of p + No. of neutron
= 2.75 × 102
A = 275
The correct answer is: 275
= 2.75 × 102
A = 275
The correct answer is: 275
Most Upvoted Answer
A singly charged positive ion is accelerated through a potential diffe...
Given information:
Potential difference (V) = 1000 V
Magnetic field (B) = 1500 Gauss = 0.15 Tesla
Radius of circular path (r) = 0.122 m
To find:
Mass number of the ion
Formula used:
The equation for the radius of the circular path of a charged particle moving in a magnetic field is given by:
r = mv / (qB)
where,
r = radius of the circular path
m = mass of the ion
v = velocity of the ion
q = charge of the ion
B = magnetic field
Solving for mass number:
Since the charge of the ion is singly charged (q = 1), we can rewrite the equation as:
r = mv / (B)
We know that the potential difference is given by:
V = qV
where,
V = potential difference
q = charge of the ion
So, we can rewrite the equation as:
V = (1/2)mv^2
Simplifying the equations, we get:
r = (2V / B)^0.5
v = (2V / m)^0.5
To eliminate the velocity (v), we substitute the value of v in terms of r into the equation for r:
r = (2V / mB)^0.5
r^2 = 2V / mB
m = 2V / (r^2B)
Substituting the given values:
m = 2 * 1000 / (0.122^2 * 0.15)
m ≈ 274.96
Since the mass number must be a whole number, we round it to the nearest whole number:
m ≈ 275
Therefore, the mass number of the ion is 275 (option A).
Potential difference (V) = 1000 V
Magnetic field (B) = 1500 Gauss = 0.15 Tesla
Radius of circular path (r) = 0.122 m
To find:
Mass number of the ion
Formula used:
The equation for the radius of the circular path of a charged particle moving in a magnetic field is given by:
r = mv / (qB)
where,
r = radius of the circular path
m = mass of the ion
v = velocity of the ion
q = charge of the ion
B = magnetic field
Solving for mass number:
Since the charge of the ion is singly charged (q = 1), we can rewrite the equation as:
r = mv / (B)
We know that the potential difference is given by:
V = qV
where,
V = potential difference
q = charge of the ion
So, we can rewrite the equation as:
V = (1/2)mv^2
Simplifying the equations, we get:
r = (2V / B)^0.5
v = (2V / m)^0.5
To eliminate the velocity (v), we substitute the value of v in terms of r into the equation for r:
r = (2V / mB)^0.5
r^2 = 2V / mB
m = 2V / (r^2B)
Substituting the given values:
m = 2 * 1000 / (0.122^2 * 0.15)
m ≈ 274.96
Since the mass number must be a whole number, we round it to the nearest whole number:
m ≈ 275
Therefore, the mass number of the ion is 275 (option A).
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A singly charged positive ion is accelerated through a potential difference of 1000Vin a mass spectrograph. It then passes through a uniform magnetic fieldB= 1500 Gauss and then deflected into a circular path of radius 0.122m. The mass number of the ion is :a)275b)200c)100d)159Correct answer is option 'A'. Can you explain this answer?
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A singly charged positive ion is accelerated through a potential difference of 1000Vin a mass spectrograph. It then passes through a uniform magnetic fieldB= 1500 Gauss and then deflected into a circular path of radius 0.122m. The mass number of the ion is :a)275b)200c)100d)159Correct answer is option 'A'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A singly charged positive ion is accelerated through a potential difference of 1000Vin a mass spectrograph. It then passes through a uniform magnetic fieldB= 1500 Gauss and then deflected into a circular path of radius 0.122m. The mass number of the ion is :a)275b)200c)100d)159Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A singly charged positive ion is accelerated through a potential difference of 1000Vin a mass spectrograph. It then passes through a uniform magnetic fieldB= 1500 Gauss and then deflected into a circular path of radius 0.122m. The mass number of the ion is :a)275b)200c)100d)159Correct answer is option 'A'. Can you explain this answer?.
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