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For an AM signal, the bandwidth is 10 kHz and the highest frequency component present is 705 kHz. The carrier frequency used for this AM signal is
- a)695 kHz
- b)700 kHz
- c)705 kHz
- d)710 kHz
Correct answer is option 'B'. Can you explain this answer?
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For an AM signal, the bandwidth is 10 kHz and the highest frequency co...
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For an AM signal, the bandwidth is 10 kHz and the highest frequency co...
Given information:
Bandwidth (B) = 10 kHz
Highest frequency component present (fmax) = 705 kHz
Calculation:
For an AM signal, the frequency spectrum can be represented as follows:
f(t) = Ac [1 + m cos(2πfmt)] cos(2πfct)
Here,
Ac = Amplitude of the carrier signal
m = Modulation index
fm = Frequency of the message signal
fc = Frequency of the carrier signal
In an AM signal, the bandwidth is given by:
B = 2fm
Therefore, the frequency of the message signal can be calculated as:
fm = B/2 = 5 kHz
Now, the highest frequency component present in the signal is given by:
fmax = fc + fm
Therefore,
fc = fmax - fm = 705 kHz - 5 kHz = 700 kHz
Hence, the carrier frequency used for this AM signal is 700 kHz.
Therefore, option B is the correct answer.
Bandwidth (B) = 10 kHz
Highest frequency component present (fmax) = 705 kHz
Calculation:
For an AM signal, the frequency spectrum can be represented as follows:
f(t) = Ac [1 + m cos(2πfmt)] cos(2πfct)
Here,
Ac = Amplitude of the carrier signal
m = Modulation index
fm = Frequency of the message signal
fc = Frequency of the carrier signal
In an AM signal, the bandwidth is given by:
B = 2fm
Therefore, the frequency of the message signal can be calculated as:
fm = B/2 = 5 kHz
Now, the highest frequency component present in the signal is given by:
fmax = fc + fm
Therefore,
fc = fmax - fm = 705 kHz - 5 kHz = 700 kHz
Hence, the carrier frequency used for this AM signal is 700 kHz.
Therefore, option B is the correct answer.
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For an AM signal, the bandwidth is 10 kHz and the highest frequency component present is 705 kHz. The carrier frequency used for this AM signal isa)695 kHzb)700 kHzc)705 kHzd)710 kHzCorrect answer is option 'B'. Can you explain this answer?
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