If a 3 input NOR gate has eight input possibilities how many of them w...
Explanation:
A NOR gate is a logic gate that outputs a high signal (1) only when all of its inputs are low (0). It acts as the complement of an OR gate.
In this case, we have a 3-input NOR gate, which means it has three input terminals. Each input terminal can have two possibilities: high (1) or low (0). Therefore, the total number of input possibilities is 2^3 = 8.
To determine how many of these input possibilities will result in a high output, we need to consider the truth table of a 3-input NOR gate:
| A | B | C | Output |
|---|---|---|--------|
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 0 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 0 |
From the truth table above, we can see that there is only one input possibility (A = 0, B = 0, C = 0) that will result in a high output (1). Therefore, the correct answer is option 'D', which states that there is only 1 input possibility that will result in a high output.
Summary:
In a 3-input NOR gate with eight input possibilities, only one of them will result in a high output.
If a 3 input NOR gate has eight input possibilities how many of them w...
A3 input XNOR GATE has how many input possibilities && how many of those possibilities will result in. aHIGH Output