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If a 3-input OR gate has eight input possibilities, how many of those possibilities will result in a HIGH output?

  • a)
    8

  • b)
    1

  • c)
    2

  • d)
    7

Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If a 3-input OR gate has eight input possibilities, how many of those ...
An OR gate outputs a HIGH value (1) if any of its inputs is HIGH. In the case of a 3-input OR gate, there are 23=823=8 possible input combinations (since each input can be either LOW (0) or HIGH (1)).


These combinations are:



  1. 000

  2. 001

  3. 010

  4. 011

  5. 100

  6. 101

  7. 110

  8. 111



Out of these, the only combination that will result in a LOW output is the first one (000), where all inputs are LOW. In all other combinations, at least one of the inputs is HIGH, which will result in a HIGH output from the OR gate.


Therefore, out of the 8 input possibilities,7 will result in a HIGH output.
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Most Upvoted Answer
If a 3-input OR gate has eight input possibilities, how many of those ...
Answer:
To determine the number of input possibilities for a 3-input AND gate that result in a HIGH output, we need to consider all the possible combinations of input values.

Truth table for a 3-input AND gate:
The truth table for a 3-input AND gate consists of 8 rows, representing all possible combinations of input values. Each row corresponds to a specific combination of input values, and the output column indicates whether the output is HIGH or LOW for that particular combination.

To analyze the truth table, we need to understand the behavior of an AND gate:
- An AND gate produces a HIGH output only when all of its inputs are HIGH.
- If any of the inputs are LOW, the output will be LOW.

Analysis of the truth table:
In the truth table for a 3-input AND gate, there are 8 rows, representing all possible combinations of input values (0 or 1). The output column indicates whether the output is HIGH (1) or LOW (0) for each combination.

We can observe that there is only one row in the truth table where all three inputs are HIGH (1), and the output is also HIGH (1). This means that there is only one input possibility that results in a HIGH output.

Therefore, the correct answer is option 'D', which states that there is only 1 input possibility for a 3-input AND gate that will result in a HIGH output.

Summary:
- The truth table for a 3-input AND gate consists of 8 rows representing all possible combinations of input values.
- An AND gate produces a HIGH output only when all of its inputs are HIGH.
- In the truth table, there is only one row where all three inputs are HIGH, resulting in a HIGH output.
- Therefore, there is only 1 input possibility for a 3-input AND gate that will result in a HIGH output.
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If a 3-input OR gate has eight input possibilities, how many of those possibilities will result in a HIGH output?a)8b)1c)2d)7Correct answer is option 'D'. Can you explain this answer?
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