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A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).
Correct answer is '250'. Can you explain this answer?
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A common emitter amplifier has voltage gain of 50, an input impedance ...
Power gain = Voltage gain x current gain
The correct answer is: 250
The correct answer is: 250
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A common emitter amplifier has voltage gain of 50, an input impedance ...
Calculating Power Gain
The power gain of an amplifier is given by the product of voltage gain and current gain. In this case, the voltage gain is 50. To calculate the current gain, we can use the formula:
Current gain = Output impedance / (Output impedance + Input impedance)
Current gain = 200Ω / (200Ω + 1000Ω)
Current gain = 0.1667
Therefore, the power gain can be calculated as:
Power gain = Voltage gain x Current gain
Power gain = 50 x 0.1667
Power gain = 8.333
Converting Power Gain to dB
To convert the power gain to dB, we use the formula:
Power gain (dB) = 10 x log10(Power gain)
Power gain (dB) = 10 x log10(8.333)
Power gain (dB) = 9.33 dB
Therefore, the power gain of the amplifier is 9.33 dB, which is closer to 10 dB than 250 dB. The correct answer should be recalculated.
The power gain of an amplifier is given by the product of voltage gain and current gain. In this case, the voltage gain is 50. To calculate the current gain, we can use the formula:
Current gain = Output impedance / (Output impedance + Input impedance)
Current gain = 200Ω / (200Ω + 1000Ω)
Current gain = 0.1667
Therefore, the power gain can be calculated as:
Power gain = Voltage gain x Current gain
Power gain = 50 x 0.1667
Power gain = 8.333
Converting Power Gain to dB
To convert the power gain to dB, we use the formula:
Power gain (dB) = 10 x log10(Power gain)
Power gain (dB) = 10 x log10(8.333)
Power gain (dB) = 9.33 dB
Therefore, the power gain of the amplifier is 9.33 dB, which is closer to 10 dB than 250 dB. The correct answer should be recalculated.
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A common emitter amplifier has voltage gain of 50, an input impedance ...
Power gain = Voltage gain x current gain
The correct answer is: 250
The correct answer is: 250
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A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).Correct answer is '250'. Can you explain this answer?
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A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).Correct answer is '250'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).Correct answer is '250'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).Correct answer is '250'. Can you explain this answer?.
A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).Correct answer is '250'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).Correct answer is '250'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).Correct answer is '250'. Can you explain this answer?.
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