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An amplifier has a standard spot noise figure F0  = 6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta = 180 K
Que: The effective input noise temperature of this amplifier is
  • a)
    2520 K
  • b)
    2120 K
  • c)
    2710 K
  • d)
    1540 K
Correct answer is option 'D'. Can you explain this answer?
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An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The a...
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An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The a...
Given data:
Standard spot noise figure F0 = 6.31 (8.0 dB)
Antenna temperature Ta = 180 K

To find: Effective input noise temperature (Te)

Formula used:
Te = (F0 - 1) * Ta

Calculation:
Substituting the given values in the above formula, we get
Te = (6.31 - 1) * 180 K
Te = 5.31 * 180 K
Te = 954.8 K

Therefore, the effective input noise temperature of this amplifier is 954.8 K (Option D).
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An amplifier has a standard spot noise figure F0 =6.31 (8.0 dB). The amplifier, that is used to amplify the output of an antenna have antenna temperature of Ta= 180 KQue: The effective input noise temperature of this amplifier isa)2520 Kb)2120 Kc)2710 Kd)1540 KCorrect answer is option 'D'. Can you explain this answer?
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