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The current i(t), through a 10 Ω resistor in series with an inductance is given by I(t) = 3 + 4 sin(100t + 450) + 4sin(300t + 600) amperes the RMS values of the current and power dissipation in the circuit are
  • a)
    √41 A, 410 W respectively
  • b)
    √45 A, 350 W respectively
  • c)
    5 A, 250 W respectively
  • d)
    11 A, 1210 W respectively
Correct answer is option 'C'. Can you explain this answer?
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The current i(t), through a 10 Ω resistor in series with an indu...
Ω resistor, is given by the equation i(t) = 5e^(-2t) A, where t is the time in seconds.
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The current i(t), through a 10 Ω resistor in series with an inductance is given by I(t) = 3 + 4 sin(100t + 450) + 4sin(300t + 600) amperes the RMS values of the current and power dissipation in the circuit area)√41 A, 410 W respectivelyb)√45 A, 350 W respectivelyc)5 A, 250 W respectivelyd)11 A, 1210 W respectivelyCorrect answer is option 'C'. Can you explain this answer?
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The current i(t), through a 10 Ω resistor in series with an inductance is given by I(t) = 3 + 4 sin(100t + 450) + 4sin(300t + 600) amperes the RMS values of the current and power dissipation in the circuit area)√41 A, 410 W respectivelyb)√45 A, 350 W respectivelyc)5 A, 250 W respectivelyd)11 A, 1210 W respectivelyCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The current i(t), through a 10 Ω resistor in series with an inductance is given by I(t) = 3 + 4 sin(100t + 450) + 4sin(300t + 600) amperes the RMS values of the current and power dissipation in the circuit area)√41 A, 410 W respectivelyb)√45 A, 350 W respectivelyc)5 A, 250 W respectivelyd)11 A, 1210 W respectivelyCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The current i(t), through a 10 Ω resistor in series with an inductance is given by I(t) = 3 + 4 sin(100t + 450) + 4sin(300t + 600) amperes the RMS values of the current and power dissipation in the circuit area)√41 A, 410 W respectivelyb)√45 A, 350 W respectivelyc)5 A, 250 W respectivelyd)11 A, 1210 W respectivelyCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The current i(t), through a 10 Ω resistor in series with an inductance is given by I(t) = 3 + 4 sin(100t + 450) + 4sin(300t + 600) amperes the RMS values of the current and power dissipation in the circuit area)√41 A, 410 W respectivelyb)√45 A, 350 W respectivelyc)5 A, 250 W respectivelyd)11 A, 1210 W respectivelyCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
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