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Mohit runs a distance of 7km 800m in going round a rectangular ground three times. What is the length of the ground if its width is 330m?
- a)670 m
- b)770 m
- c)870 m
- d)970 m
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Mohit runs a distance of 7km 800m in going round a rectangular ground ...
Here, 3 × perimeter of rectangular ground = 7800 m
⇒ 3 [2 (l + b)] = 7800
⇒ 3 [2 (l + b)] = 7800
Most Upvoted Answer
Mohit runs a distance of 7km 800m in going round a rectangular ground ...
Given:
Distance covered by Mohit in going round the rectangular ground three times = 7 km 800 m
We know that 1 km = 1000 m.
So, the distance covered by Mohit in going round the ground three times = 7 km + 800 m = 7000 m + 800 m = 7800 m.
Let's assume the length of the rectangular ground is L meters.
To go around the rectangular ground, Mohit needs to cover the perimeter of the ground three times.
Formula to calculate the perimeter of a rectangle:
Perimeter = 2(length + width)
In this case, the width is given as 330 m.
To find the length of the ground, we need to equate the perimeter to the distance covered by Mohit.
Equating the perimeter to the distance covered:
3(2L + 330) = 7800
Simplifying the equation:
6L + 990 = 7800
6L = 7800 - 990
6L = 6810
L = 6810/6
L = 1135
Therefore, the length of the rectangular ground is 1135 meters.
Hence, the correct answer is option D) 970 m.
Distance covered by Mohit in going round the rectangular ground three times = 7 km 800 m
We know that 1 km = 1000 m.
So, the distance covered by Mohit in going round the ground three times = 7 km + 800 m = 7000 m + 800 m = 7800 m.
Let's assume the length of the rectangular ground is L meters.
To go around the rectangular ground, Mohit needs to cover the perimeter of the ground three times.
Formula to calculate the perimeter of a rectangle:
Perimeter = 2(length + width)
In this case, the width is given as 330 m.
To find the length of the ground, we need to equate the perimeter to the distance covered by Mohit.
Equating the perimeter to the distance covered:
3(2L + 330) = 7800
Simplifying the equation:
6L + 990 = 7800
6L = 7800 - 990
6L = 6810
L = 6810/6
L = 1135
Therefore, the length of the rectangular ground is 1135 meters.
Hence, the correct answer is option D) 970 m.
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Mohit runs a distance of 7km 800m in going round a rectangular ground three times. What is the length of the ground if its width is 330m?a)670 mb)770 mc)870 md)970 mCorrect answer is option 'D'. Can you explain this answer?
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