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Force 3i + 2j + 5k and 2i + j - 3k are acting on a particle and displace it from the point 2i - 2j + 10k, then the work done by the force is
  • a)
    30 unit
  • b)
    36 unit
  • c)
    24 unit
  • d)
    18 unit
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Force 3i + 2j + 5k and 2i + j - 3k are acting on a particle and displa...
Resultant force F = 5i + 3j + 2k and displacement d = 2i - 2j + 10k, then Work done W = F.cl = 10 - 6 + 20 = 24 unit.
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Most Upvoted Answer
Force 3i + 2j + 5k and 2i + j - 3k are acting on a particle and displa...
Given:
Force 1 = 3i + 2j + 5k
Force 2 = 2i + j - 3k
Displacement = 2i - 2j + 10k

To calculate the work done by the forces, we can use the formula:

Work = Force · Displacement

where "." represents the dot product.

1. Calculate the dot product of Force 1 and Displacement:
(3i + 2j + 5k) · (2i - 2j + 10k) = (3*2) + (2*-2) + (5*10) = 6 - 4 + 50 = 52

2. Calculate the dot product of Force 2 and Displacement:
(2i + j - 3k) · (2i - 2j + 10k) = (2*2) + (1*-2) + (-3*10) = 4 - 2 - 30 = -28

3. Add the dot products of both forces:
Work = 52 + (-28) = 24 units

Therefore, the work done by the forces is 24 units.
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Force 3i + 2j + 5k and 2i + j - 3k are acting on a particle and displace it from the point 2i - 2j + 10k, then the work done by the force isa)30 unitb)36 unitc)24 unitd)18 unitCorrect answer is option 'C'. Can you explain this answer?
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