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Efficiency of a Carnot engine is 75%. If the cycle direction is reversed, COP of the reversedCarnot cycle is
- a)1.33
- b)0.75
- c)0.33
- d)1.75
Correct answer is option 'C'. Can you explain this answer?
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Efficiency of Carnot Engine:
Efficiency of a Carnot engine is given by the formula:
\[ \text{Efficiency} = 1 - \frac{T_c}{T_h} \]
Given that the efficiency is 75%, we can write:
\[ \frac{T_h - T_c}{T_h} = 0.75 \]
\[ T_h = 4T_c \]
Coefficient of Performance (COP) of the Reversed Carnot Cycle:
The coefficient of performance for a reversed Carnot cycle is given by the formula:
\[ \text{COP} = \frac{T_c}{T_h - T_c} \]
Substitute the values of \(T_h\) and \(T_c\) in the above formula:
\[ \text{COP} = \frac{T_c}{4T_c - T_c} \]
\[ \text{COP} = \frac{T_c}{3T_c} = \frac{1}{3} \]
Therefore, the COP of the reversed Carnot cycle is 0.33, which corresponds to option 'C'.
Efficiency of a Carnot engine is given by the formula:
\[ \text{Efficiency} = 1 - \frac{T_c}{T_h} \]
Given that the efficiency is 75%, we can write:
\[ \frac{T_h - T_c}{T_h} = 0.75 \]
\[ T_h = 4T_c \]
Coefficient of Performance (COP) of the Reversed Carnot Cycle:
The coefficient of performance for a reversed Carnot cycle is given by the formula:
\[ \text{COP} = \frac{T_c}{T_h - T_c} \]
Substitute the values of \(T_h\) and \(T_c\) in the above formula:
\[ \text{COP} = \frac{T_c}{4T_c - T_c} \]
\[ \text{COP} = \frac{T_c}{3T_c} = \frac{1}{3} \]
Therefore, the COP of the reversed Carnot cycle is 0.33, which corresponds to option 'C'.
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Efficiency of a Carnot engine is 75%. If the cycle direction is reversed, COP of the reversedCarnot cycle isa)1.33b)0.75c)0.33d)1.75Correct answer is option 'C'. Can you explain this answer?
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