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Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).
Passage l
Isotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.
Q. Ratio of rate constants of 14O to 15O is
- a)1.75
- b)0.573
- c)1.14
- d)0.873
Correct answer is option 'A'. Can you explain this answer?
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Direction (Q. Nos. 22-27) This section contains a passage describing t...
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Direction (Q. Nos. 22-27) This section contains a passage describing t...
Radioactive decay and transforms into other elements over time. This process is known as radioactive isotopic decay. The rate at which this decay occurs can be measured using a technique called radiometric dating.
One common isotope of oxygen is oxygen-15, which has a mass number of 15. This isotope is unstable and undergoes radioactive decay with a half-life of about 122 seconds. During this decay, the oxygen-15 isotope transforms into nitrogen-15 through the emission of a beta particle.
Radiometric dating is based on the principle that radioactive isotopes decay at a constant rate over time. By measuring the ratio of the parent isotope (oxygen-15) to the decay product (nitrogen-15) in a sample, scientists can determine how long it has been since the sample formed.
This technique has been used to date various materials, including rocks, fossils, and archaeological artifacts. By determining the age of these materials, scientists can gain insight into the Earth's history and the age of ancient civilizations.
22. Radiometric dating is based on the principle that radioactive isotopes decay at a _______ rate over time.
(a) variable
(b) decreasing
(c) increasing
(d) constant
Answer: (d) constant
23. Oxygen-15 undergoes radioactive decay and transforms into _______.
(a) oxygen-16
(b) nitrogen-14
(c) nitrogen-15
(d) carbon-14
Answer: (c) nitrogen-15
One common isotope of oxygen is oxygen-15, which has a mass number of 15. This isotope is unstable and undergoes radioactive decay with a half-life of about 122 seconds. During this decay, the oxygen-15 isotope transforms into nitrogen-15 through the emission of a beta particle.
Radiometric dating is based on the principle that radioactive isotopes decay at a constant rate over time. By measuring the ratio of the parent isotope (oxygen-15) to the decay product (nitrogen-15) in a sample, scientists can determine how long it has been since the sample formed.
This technique has been used to date various materials, including rocks, fossils, and archaeological artifacts. By determining the age of these materials, scientists can gain insight into the Earth's history and the age of ancient civilizations.
22. Radiometric dating is based on the principle that radioactive isotopes decay at a _______ rate over time.
(a) variable
(b) decreasing
(c) increasing
(d) constant
Answer: (d) constant
23. Oxygen-15 undergoes radioactive decay and transforms into _______.
(a) oxygen-16
(b) nitrogen-14
(c) nitrogen-15
(d) carbon-14
Answer: (c) nitrogen-15
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Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer?
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Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer?.
Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer?.
Solutions for Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Direction (Q. Nos. 22-27) This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).Passage lIsotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14O and 15O, Also t50 (14O) = 71s, t50 (15O) = 124s.Q.Ratio of rate constants of 14O to 15Oisa)1.75b)0.573c)1.14d)0.873Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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