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DIRECTIONS for the question: Solve the following question and mark the best possible option.
P, Q and R are positive integers such that P+Q+R=100. Find the probability that P >20, Q > 10 and  R>20.?
  • a)
    23/99
  • b)
    8/33
  • c)
    2/9
  • d)
    1/3
Correct answer is option 'B'. Can you explain this answer?
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Given:
- P, Q, and R are positive integers such that P + Q + R = 100
- We need to find the probability that P > 20, Q > 10, and R > 20

Total number of possibilities:
- Since P, Q, and R are positive integers and their sum is 100, the total number of possibilities can be calculated using the formula for distributing identical objects into different boxes, which is (n + r - 1)C(r - 1), where n is the total sum and r is the number of variables.
- So, the total number of possibilities = (100 + 3 - 1)C(3 - 1) = 102C2 = 5151

Finding the favorable outcomes:
- To find the favorable outcomes, we need to consider the cases when P > 20, Q > 10, and R > 20.
- Let's assume P = 21, then the sum of Q and R should be 79. Since Q and R are positive integers, the possibilities for Q and R can be calculated using the same formula as above.
- For P = 21, the number of possibilities for Q and R = (79 + 2 - 1)C(2 - 1) = 80C1 = 80
- Similarly, for P = 22, 23, ..., 80, the number of possibilities for Q and R will be 78, 77, ..., 21 respectively.

Calculating the probability:
- Adding up all the favorable outcomes, we get 80 + 78 + 77 + ... + 1 = 3160
- Therefore, the probability = 3160 / 5151 = 8 / 33
Therefore, the correct answer is option 'b) 8/33'.
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DIRECTIONS for the question:Solve the following question and mark the best possible option.P, Q and R are positive integers such that P+Q+R=100. Find the probability that P >20, Q > 10 and R>20.?a)23/99b)8/33c)2/9d)1/3Correct answer is option 'B'. Can you explain this answer?
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