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Elevation in boiling point of a solution of non-electrolyte in non-polar solvent (toluene) is 0.3°. Mole fraction elevation constant of non-polar solvent is 36.1 K. Thus, molality (mol kg-1) of the solution is
- a)8.31 x 10-3
- b)0.091
- c)10.98
- d)1.27
Correct answer is option 'B'. Can you explain this answer?
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Elevation in boiling point of a solution of non-electrolyte in non-pol...
(b) In terms of mole fraction elevation constant
Thus, solute = 0.3 mole
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Elevation in boiling point of a solution of non-electrolyte in non-pol...
Given:
Elevation in boiling point (ΔTb) = 0.3 K
Mole fraction elevation constant (Kb) = 36.1 K/mol
We need to find the molality (m) of the solution.
Formula:
ΔTb = Kb . m
where ΔTb = elevation in boiling point, Kb = mole fraction elevation constant, and m = molality of the solution
Solution:
Substituting the given values in the formula, we get:
0.3 K = 36.1 K/mol x m
m = 0.3 K / 36.1 K/mol = 0.00831 mol/kg
Converting molality to grams:
Molar mass of toluene = 92 g/mol (approx.)
1 kg of toluene contains 1000/92 = 10.87 moles of toluene
So, the mass of toluene in the solution = (1 - 0.00831) kg x 1000 g/kg = 991.69 g
The mass of the solute (non-electrolyte) in the solution = 8.31 g
Therefore, the molality of the solution = (8.31 g / 92 g/mol) / 0.99169 kg = 0.0908 mol/kg
Rounding off to two significant figures, we get:
molality of the solution = 0.091 mol/kg
Hence, option B is the correct answer.
Elevation in boiling point (ΔTb) = 0.3 K
Mole fraction elevation constant (Kb) = 36.1 K/mol
We need to find the molality (m) of the solution.
Formula:
ΔTb = Kb . m
where ΔTb = elevation in boiling point, Kb = mole fraction elevation constant, and m = molality of the solution
Solution:
Substituting the given values in the formula, we get:
0.3 K = 36.1 K/mol x m
m = 0.3 K / 36.1 K/mol = 0.00831 mol/kg
Converting molality to grams:
Molar mass of toluene = 92 g/mol (approx.)
1 kg of toluene contains 1000/92 = 10.87 moles of toluene
So, the mass of toluene in the solution = (1 - 0.00831) kg x 1000 g/kg = 991.69 g
The mass of the solute (non-electrolyte) in the solution = 8.31 g
Therefore, the molality of the solution = (8.31 g / 92 g/mol) / 0.99169 kg = 0.0908 mol/kg
Rounding off to two significant figures, we get:
molality of the solution = 0.091 mol/kg
Hence, option B is the correct answer.
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Elevation in boiling point of a solution of non-electrolyte in non-polar solvent (toluene) is 0.3°. Mole fraction elevation constant of non-polar solvent is 36.1 K. Thus, molality (mol kg-1) of the solution isa)8.31 x 10-3b)0.091c)10.98d)1.27Correct answer is option 'B'. Can you explain this answer?
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Elevation in boiling point of a solution of non-electrolyte in non-polar solvent (toluene) is 0.3°. Mole fraction elevation constant of non-polar solvent is 36.1 K. Thus, molality (mol kg-1) of the solution isa)8.31 x 10-3b)0.091c)10.98d)1.27Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Elevation in boiling point of a solution of non-electrolyte in non-polar solvent (toluene) is 0.3°. Mole fraction elevation constant of non-polar solvent is 36.1 K. Thus, molality (mol kg-1) of the solution isa)8.31 x 10-3b)0.091c)10.98d)1.27Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Elevation in boiling point of a solution of non-electrolyte in non-polar solvent (toluene) is 0.3°. Mole fraction elevation constant of non-polar solvent is 36.1 K. Thus, molality (mol kg-1) of the solution isa)8.31 x 10-3b)0.091c)10.98d)1.27Correct answer is option 'B'. Can you explain this answer?.
Elevation in boiling point of a solution of non-electrolyte in non-polar solvent (toluene) is 0.3°. Mole fraction elevation constant of non-polar solvent is 36.1 K. Thus, molality (mol kg-1) of the solution isa)8.31 x 10-3b)0.091c)10.98d)1.27Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Elevation in boiling point of a solution of non-electrolyte in non-polar solvent (toluene) is 0.3°. Mole fraction elevation constant of non-polar solvent is 36.1 K. Thus, molality (mol kg-1) of the solution isa)8.31 x 10-3b)0.091c)10.98d)1.27Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Elevation in boiling point of a solution of non-electrolyte in non-polar solvent (toluene) is 0.3°. Mole fraction elevation constant of non-polar solvent is 36.1 K. Thus, molality (mol kg-1) of the solution isa)8.31 x 10-3b)0.091c)10.98d)1.27Correct answer is option 'B'. Can you explain this answer?.
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