Total number of non abelian groups of order 23 . 34. 5 is __________.C...
Partitions of 3 are three namely
3 = 3,2 + 1, 1 +1 +1.
Partition of 4 are five namely
4 = 4, 3 + 1, 2 + 2, 2 + 1 +1, 1 +1 +1 +1.
Partition of 1 is only one 1 = 1
Thus there are (I) non isomorphic abelian group of order 2.
(II) five non isomorphic abelian group of order 34. and
(III) One abelian group of order 5.
Hence total number of non abelian group of order
23. 34. 5 = 3 x 5 x 1 = 1
=15
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Total number of non abelian groups of order 23 . 34. 5 is __________.C...
Partitions of 3 are three namely
3 = 3,2 + 1, 1 +1 +1.
Partition of 4 are five namely
4 = 4, 3 + 1, 2 + 2, 2 + 1 +1, 1 +1 +1 +1.
Partition of 1 is only one 1 = 1
Thus there are (I) non isomorphic abelian group of order 2.
(II) five non isomorphic abelian group of order 34. and
(III) One abelian group of order 5.
Hence total number of non abelian group of order
23. 34. 5 = 3 x 5 x 1 = 1
=15
Total number of non abelian groups of order 23 . 34. 5 is __________.C...
The total number of non-abelian groups of order 23 * 34 * 5 is 15. Let's break down the steps to understand why this is the correct answer.
Step 1: Prime Factorization
First, we need to find the prime factorization of the given number. The prime factorization of 23 * 34 * 5 is as follows:
23 = 23^1
34 = 2^1 * 17^1
5 = 5^1
Step 2: Counting Non-Abelian Groups
To determine the number of non-abelian groups of a given order, we need to consider the possible combinations of prime powers.
For a prime power p^n, there are two possibilities:
1. The group is abelian, which means it is isomorphic to a direct product of cyclic groups of prime power order.
2. The group is non-abelian.
Since we are interested in counting only the non-abelian groups, we need to exclude the abelian ones.
Step 3: Counting Abelian Groups
To count the number of abelian groups, we need to consider each prime power separately.
For the prime power 23^1, there is only one abelian group of order 23^1, which is the cyclic group of order 23.
For the prime power 2^1, there are two abelian groups of order 2^1: the cyclic group of order 2, and the trivial group.
For the prime power 17^1, there is only one abelian group of order 17^1, which is the cyclic group of order 17.
For the prime power 5^1, there is only one abelian group of order 5^1, which is the cyclic group of order 5.
Step 4: Calculating Non-Abelian Groups
To calculate the number of non-abelian groups, we subtract the number of abelian groups from the total number of groups.
For the prime power 23^1, there is only one group of order 23^1.
For the prime power 2^1, there is only one group of order 2^1.
For the prime power 17^1, there is only one group of order 17^1.
For the prime power 5^1, there is only one group of order 5^1.
Multiplying these counts together, we get 1 * 1 * 1 * 1 = 1.
Therefore, the total number of non-abelian groups of order 23 * 34 * 5 is 1.
However, it is mentioned that the correct answer is 15, which means there may be a mistake in the given information or question. Please double-check the question or provide more context if necessary.