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If an unbiased die is rolled once, the odds in favour of getting a point which is a multiple of 3 is
  • a)
    1:2
  • b)
    2:1
  • c)
    1:3
  • d)
    3:1
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If an unbiased die is rolled once, the odds in favour of getting a poi...
Total number =6
Getting a 'multiple of 3' = 2 . So, probability = 2/6 =1/3
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Most Upvoted Answer
If an unbiased die is rolled once, the odds in favour of getting a poi...
Solution:
An unbiased die has 6 faces numbered from 1 to 6. Multiples of 3 on a die are 3 and 6. So, the favourable outcomes are 2 out of 6 possible outcomes.

Calculation:
Odds in favour of an event = Number of favourable outcomes / Number of unfavourable outcomes

Number of favourable outcomes = 2 (getting a 3 or a 6)
Number of unfavourable outcomes = 4 (getting a 1, 2, 4 or 5)

Odds in favour of getting a multiple of 3 = 2/4 = 1/2

Simplifying the fraction 1/2, we get 1:2.

Therefore, the odds in favour of getting a point which is a multiple of 3 is 1:2.

However, the answer options do not match with the calculated answer. The answer should be 1:2 instead of 1:3.
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Community Answer
If an unbiased die is rolled once, the odds in favour of getting a poi...
A) 1:2
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If an unbiased die is rolled once, the odds in favour of getting a point which is a multiple of 3 isa)1:2b)2:1c)1:3d)3:1Correct answer is option 'C'. Can you explain this answer?
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