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Comprehension Type
This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)
Passage
1 kg of 1 molal aqueous solution of sucrose is cooled and maintained at - 3.534° C. Kf (H20) = 1.86 K mol-1kg
Q.
 Relative lowering of vapour pressure 
  • a)
    0.020
  • b)
    55.56
  • c)
    56.55
  • d)
    0.018
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Comprehension TypeThis section contains a passage describing theory, e...
Molality = 1 mol kg-1, Solute (sucrose ) =1 mole Solvent (H20 ) =1 kg = 1000 g = 55.55 moles
By Raou lt’s law for binary mixture of non -volatile solute in volatile solvent, relative lowering of vapour pressure = Xsoiute
S ucrose solution is maintained at -3 .534 °C .
Thus, ΔTf = 3.534°C
Total mass of 1 molal solution = 1000 g (solvent) + 342 g (solute) = 1342 g
1342 g solution contains sucrose = 342 g
1000 g solution contains sucrose = 
H20 present in 1000 g solution = 1000 - 255 = 745 g
Solvent actually required to keep 255g sucrose in solution at -3 .534°C = w2
Thus , ice form ed = 745 - 392 = 353 g (in solid state ) 
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Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)Passage1 kg of 1 molal aqueous solution of sucrose is cooled and maintained at - 3.534° C. Kf (H20) = 1.86 K mol-1kgQ.Relative lowering of vapour pressurea)0.020b)55.56c)56.55d)0.018Correct answer is option 'D'. Can you explain this answer?
Question Description
Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)Passage1 kg of 1 molal aqueous solution of sucrose is cooled and maintained at - 3.534° C. Kf (H20) = 1.86 K mol-1kgQ.Relative lowering of vapour pressurea)0.020b)55.56c)56.55d)0.018Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)Passage1 kg of 1 molal aqueous solution of sucrose is cooled and maintained at - 3.534° C. Kf (H20) = 1.86 K mol-1kgQ.Relative lowering of vapour pressurea)0.020b)55.56c)56.55d)0.018Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)Passage1 kg of 1 molal aqueous solution of sucrose is cooled and maintained at - 3.534° C. Kf (H20) = 1.86 K mol-1kgQ.Relative lowering of vapour pressurea)0.020b)55.56c)56.55d)0.018Correct answer is option 'D'. Can you explain this answer?.
Solutions for Comprehension TypeThis section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d)Passage1 kg of 1 molal aqueous solution of sucrose is cooled and maintained at - 3.534° C. Kf (H20) = 1.86 K mol-1kgQ.Relative lowering of vapour pressurea)0.020b)55.56c)56.55d)0.018Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
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