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The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113 g cm-3. Thus, the freezing point of the mixture is
- a)-33.4oC
- b)+33.4oC
- c)-7.40C
- d)+7.40C
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The coolant usually contains a solution of antifreeze prepared by mixi...
(a) S o lu te is e th y le ne g ly c o l = 1 m L = 1.113 g (w1)
∴ Freezing point = 0 - 33.39° = - 33.390
Most Upvoted Answer
The coolant usually contains a solution of antifreeze prepared by mixi...
Understanding Coolant Solutions
Coolant solutions often use antifreeze to lower the freezing point of water. Ethylene glycol is a common antifreeze component.
Composition of the Mixture
- The mixture is prepared by mixing equal volumes of ethylene glycol and water.
- Ethylene glycol (C2H4(OH)2) has a density of 1.113 g/cm³.
Freezing Point Depression
- The freezing point of pure water is 0°C.
- When antifreeze is added, the freezing point lowers due to the colligative properties of the solution.
- The more solute (ethylene glycol) present in the solution, the lower the freezing point.
Calculating Freezing Point
- Ethylene glycol has a freezing point of -13°C.
- A solution of 50% ethylene glycol and 50% water can significantly decrease the freezing point.
- The freezing point depression can be calculated using the formula: ΔTf = i * Kf * m, where:
- ΔTf = freezing point depression
- i = van 't Hoff factor (for ethylene glycol, i = 1)
- Kf = freezing point depression constant for water (1.86 °C kg/mol)
- m = molality of the solution
Conclusion
Through calculations and understanding of colligative properties, the freezing point of the ethylene glycol-water mixture is determined to be approximately -33.4°C. Thus, the correct answer is option 'A'. This low freezing point makes the coolant effective in preventing engine freezing in cold temperatures.
Coolant solutions often use antifreeze to lower the freezing point of water. Ethylene glycol is a common antifreeze component.
Composition of the Mixture
- The mixture is prepared by mixing equal volumes of ethylene glycol and water.
- Ethylene glycol (C2H4(OH)2) has a density of 1.113 g/cm³.
Freezing Point Depression
- The freezing point of pure water is 0°C.
- When antifreeze is added, the freezing point lowers due to the colligative properties of the solution.
- The more solute (ethylene glycol) present in the solution, the lower the freezing point.
Calculating Freezing Point
- Ethylene glycol has a freezing point of -13°C.
- A solution of 50% ethylene glycol and 50% water can significantly decrease the freezing point.
- The freezing point depression can be calculated using the formula: ΔTf = i * Kf * m, where:
- ΔTf = freezing point depression
- i = van 't Hoff factor (for ethylene glycol, i = 1)
- Kf = freezing point depression constant for water (1.86 °C kg/mol)
- m = molality of the solution
Conclusion
Through calculations and understanding of colligative properties, the freezing point of the ethylene glycol-water mixture is determined to be approximately -33.4°C. Thus, the correct answer is option 'A'. This low freezing point makes the coolant effective in preventing engine freezing in cold temperatures.
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The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113 g cm-3. Thus, the freezing point of the mixture isa)-33.4oCb)+33.4oCc)-7.40Cd)+7.40CCorrect answer is option 'A'. Can you explain this answer?
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The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113 g cm-3. Thus, the freezing point of the mixture isa)-33.4oCb)+33.4oCc)-7.40Cd)+7.40CCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113 g cm-3. Thus, the freezing point of the mixture isa)-33.4oCb)+33.4oCc)-7.40Cd)+7.40CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113 g cm-3. Thus, the freezing point of the mixture isa)-33.4oCb)+33.4oCc)-7.40Cd)+7.40CCorrect answer is option 'A'. Can you explain this answer?.
The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113 g cm-3. Thus, the freezing point of the mixture isa)-33.4oCb)+33.4oCc)-7.40Cd)+7.40CCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113 g cm-3. Thus, the freezing point of the mixture isa)-33.4oCb)+33.4oCc)-7.40Cd)+7.40CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coolant usually contains a solution of antifreeze prepared by mixing equal volumes of ethylene glycol C2H4(OH)2 and water. The density of ethylene glycol is 1.113 g cm-3. Thus, the freezing point of the mixture isa)-33.4oCb)+33.4oCc)-7.40Cd)+7.40CCorrect answer is option 'A'. Can you explain this answer?.
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