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Some ethylene glycol , HOCH2CH2OH, is added to your car's cooling system along with 5 kg of water. If the freezing point of water-glycol solution is -15 degree centigrade ,what is the boiling point of the solution? ( Kb =0.52 K kg /mol and Kf = 1.86 K kg/mol for water)?
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Solution:

Given:
Amount of ethylene glycol = ?
Amount of water = 5 kg
Freezing point of solution = -15°C
Kb = 0.52 K kg/mol
Kf = 1.86 K kg/mol

To find: Boiling point of the solution

Formula used:
ΔTf = Kf × m
ΔTb = Kb × m

where ΔTf is the change in freezing point,
ΔTb is the change in boiling point,
Kf is the molal freezing point constant,
Kb is the molal boiling point constant,
and m is the molality of the solution.

Calculation:
1. Calculation of molality of the solution
Molality (m) = moles of solute ÷ mass of solvent (in kg)

The molecular weight of ethylene glycol (C2H6O2) = 2 × 12 + 6 × 1 + 2 × 16 = 62 g/mol
Let's assume that x kg of ethylene glycol is added to the solution.
So, the mass of the solution = (5 + x) kg
Number of moles of ethylene glycol = mass ÷ molar mass = x ÷ 62
Molality of the solution = (x ÷ 62) ÷ 5 = x ÷ 310

2. Calculation of the change in freezing point
ΔTf = Kf × m
ΔTf = 1.86 × (x ÷ 310)
ΔTf = (1.86/310) x

3. Calculation of the freezing point of the solution
The freezing point of the solution = Freezing point of pure water - ΔTf
-15 = 0 - ΔTf
ΔTf = 15°C

Substituting the value of ΔTf in the equation,
15 = (1.86/310) x
x = 100 g

So, 100 g of ethylene glycol is added to the solution.

4. Calculation of the change in boiling point
ΔTb = Kb × m
ΔTb = 0.52 × (x ÷ 310)
ΔTb = (0.52/310) x

5. Calculation of the boiling point of the solution
The boiling point of the solution = Boiling point of pure water + ΔTb
Let's assume that the boiling point of pure water is 100°C.
Boiling point of the solution = 100 + ΔTb
Boiling point of the solution = 100 + (0.52/310) x
Boiling point of the solution = 100 + 0.168°C
Boiling point of the solution = 100.168°C

Therefore, the boiling point of the water-glycol solution is 100.168°C.
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Direction: Read the passage given below and answer the following questions:Boiling point or freezing point of liquid solution would be affected by the dissolved solids in the liquid phase. A soluble solid in solution has the effect of raising its boiling point and depressing its freezing point. The addition of non-volatile substances to a solvent decreases the vapour pressure and the added solute particles affect the formation of pure solvent crystals.According to many researches the decrease in freezing point directly correlated to the concentration of solutes dissolved in the solvent. This phenomenon is expressed as freezing point depression and it is useful for several applications such as freeze concentration of liquid food and to find the molar mass of an unknown solute in the solution. Freeze concentration is a high quality liquid food concentration method where water is removed by forming ice crystals. This is done by cooling the liquid food below the freezing point of the solution. The freezing point depression is referred as a colligative property and it is proportional to the molar concentration of the solution (m), along with vapour pressure lowering, boiling point elevation, and osmotic pressure. These are physical characteristics of solutions that depend only on the identity of the solvent and the concentration of the solute. The characters are not depending on the solute’s identity.Q.Colligative properties are

Some ethylene glycol , HOCH2CH2OH, is added to your car's cooling system along with 5 kg of water. If the freezing point of water-glycol solution is -15 degree centigrade ,what is the boiling point of the solution? ( Kb =0.52 K kg /mol and Kf = 1.86 K kg/mol for water)?
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Some ethylene glycol , HOCH2CH2OH, is added to your car's cooling system along with 5 kg of water. If the freezing point of water-glycol solution is -15 degree centigrade ,what is the boiling point of the solution? ( Kb =0.52 K kg /mol and Kf = 1.86 K kg/mol for water)? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Some ethylene glycol , HOCH2CH2OH, is added to your car's cooling system along with 5 kg of water. If the freezing point of water-glycol solution is -15 degree centigrade ,what is the boiling point of the solution? ( Kb =0.52 K kg /mol and Kf = 1.86 K kg/mol for water)? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Some ethylene glycol , HOCH2CH2OH, is added to your car's cooling system along with 5 kg of water. If the freezing point of water-glycol solution is -15 degree centigrade ,what is the boiling point of the solution? ( Kb =0.52 K kg /mol and Kf = 1.86 K kg/mol for water)?.
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