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Total vapour pressure of mixture of 1 mole of a volatile component A (p°A = 100 mm Hg) and 3 moles of volatile component B(p°B = 60 mm Hg) is 75 mm Hg. For such case,a)positive deviation frm raults lawb)negative deviation from raults lawc)boiling point is loweredd)force of attraction between A and B is less than between A and A,A and BCorrect answer is option 'A,C,D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Total vapour pressure of mixture of 1 mole of a volatile component A (p°A = 100 mm Hg) and 3 moles of volatile component B(p°B = 60 mm Hg) is 75 mm Hg. For such case,a)positive deviation frm raults lawb)negative deviation from raults lawc)boiling point is loweredd)force of attraction between A and B is less than between A and A,A and BCorrect answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Total vapour pressure of mixture of 1 mole of a volatile component A (p°A = 100 mm Hg) and 3 moles of volatile component B(p°B = 60 mm Hg) is 75 mm Hg. For such case,a)positive deviation frm raults lawb)negative deviation from raults lawc)boiling point is loweredd)force of attraction between A and B is less than between A and A,A and BCorrect answer is option 'A,C,D'. Can you explain this answer?.

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Here you can find the meaning of Total vapour pressure of mixture of 1 mole of a volatile component A (p°A = 100 mm Hg) and 3 moles of volatile component B(p°B = 60 mm Hg) is 75 mm Hg. For such case,a)positive deviation frm raults lawb)negative deviation from raults lawc)boiling point is loweredd)force of attraction between A and B is less than between A and A,A and BCorrect answer is option 'A,C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Total vapour pressure of mixture of 1 mole of a volatile component A (p°A = 100 mm Hg) and 3 moles of volatile component B(p°B = 60 mm Hg) is 75 mm Hg. For such case,a)positive deviation frm raults lawb)negative deviation from raults lawc)boiling point is loweredd)force of attraction between A and B is less than between A and A,A and BCorrect answer is option 'A,C,D'. Can you explain this answer?, a detailed solution for Total vapour pressure of mixture of 1 mole of a volatile component A (p°A = 100 mm Hg) and 3 moles of volatile component B(p°B = 60 mm Hg) is 75 mm Hg. For such case,a)positive deviation frm raults lawb)negative deviation from raults lawc)boiling point is loweredd)force of attraction between A and B is less than between A and A,A and BCorrect answer is option 'A,C,D'. Can you explain this answer? has been provided alongside types of Total vapour pressure of mixture of 1 mole of a volatile component A (p°A = 100 mm Hg) and 3 moles of volatile component B(p°B = 60 mm Hg) is 75 mm Hg. For such case,a)positive deviation frm raults lawb)negative deviation from raults lawc)boiling point is loweredd)force of attraction between A and B is less than between A and A,A and BCorrect answer is option 'A,C,D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Total vapour pressure of mixture of 1 mole of a volatile component A (p°A = 100 mm Hg) and 3 moles of volatile component B(p°B = 60 mm Hg) is 75 mm Hg. For such case,a)positive deviation frm raults lawb)negative deviation from raults lawc)boiling point is loweredd)force of attraction between A and B is less than between A and A,A and BCorrect answer is option 'A,C,D'. Can you explain this answer? tests, examples and also practice Class 12 tests.