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pH of Ba(OH)2 solution is 12. Number of millimoles present in 100 mL of Ba(OH)2 solution is
  • a)
    0.50
  • b)
    1
  • c)
    0.05
  • d)
    0.10
Correct answer is option 'A'. Can you explain this answer?
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PH of Ba(OH)2 solution is 12. Number of millimoles present in 100 mL of Ba(OH)2 solution is:

To find the number of millimoles present in the solution, we need to first understand the concept of pH and the dissociation of Ba(OH)2.

1. Understanding pH:
pH is a measure of the acidity or alkalinity of a solution. It is defined as the negative logarithm of the hydrogen ion concentration ([H+]) in the solution. The pH scale ranges from 0 to 14, where pH 7 is considered neutral, pH less than 7 is acidic, and pH greater than 7 is alkaline.

2. Dissociation of Ba(OH)2:
Ba(OH)2 is a strong base that dissociates completely in water. It can be represented by the following equation:
Ba(OH)2 -> Ba2+ + 2OH-

This means that for every mole of Ba(OH)2, 1 mole of Ba2+ ions and 2 moles of OH- ions are produced.

3. Relationship between pH and pOH:
Since Ba(OH)2 is a strong base, it dissociates completely into OH- ions. The concentration of OH- ions can be used to calculate the pOH of the solution, which is related to pH by the equation:
pH + pOH = 14

Given that the pH of the Ba(OH)2 solution is 12, we can calculate the pOH as follows:
pOH = 14 - pH = 14 - 12 = 2

4. Calculating the concentration of OH- ions:
The pOH can be used to calculate the concentration of OH- ions using the equation:
pOH = -log[OH-]

2 = -log[OH-]
10^-2 = [OH-]

Therefore, the concentration of OH- ions in the solution is 0.01 M.

5. Calculating the number of millimoles:
The concentration of OH- ions is given in moles per liter (M). To convert it to millimoles per milliliter (mM), we need to multiply by the volume of the solution.

Concentration of OH- ions = 0.01 M
Volume of solution = 100 mL = 0.1 L

Number of millimoles = Concentration x Volume in milliliters
Number of millimoles = 0.01 M x 0.1 L x 1000 mL/L = 1 mM

Therefore, the number of millimoles present in 100 mL of Ba(OH)2 solution is 1 mM.

Hence, option 'A' is the correct answer.
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pH of Ba(OH)2 solution is 12. Number of millimoles present in 100 mL of Ba(OH)2 solution isa)0.50b)1c)0.05d)0.10Correct answer is option 'A'. Can you explain this answer?
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