Which of the following aqueous solutions has the highest concentration...
Explanation:
a) 0.208 M Na2SO4
- In 0.208 M Na2SO4 solution, there are 2 moles of Na+ ions for every mole of Na2SO4.
- Therefore, the concentration of Na+ ions is 2 times the concentration of Na2SO4, which is 0.208 M x 2 = 0.416 M Na+.
b) A solution containing 1.05 g NaCl/100 mL
- To find the concentration of Na in this solution, we need to convert grams of NaCl to moles of Na.
- The molar mass of NaCl is 58.44 g/mol, so 1.05 g of NaCl is equal to 1.05 g / 58.44 g/mol = 0.018 moles of NaCl.
- Since NaCl dissociates into Na+ and Cl- ions in solution, there are 0.018 moles of Na+ ions in the solution.
- The concentration of Na+ ions is 0.018 moles / 0.1 L = 0.18 M Na+.
c) A solution having 14.7 mg Na /mL
- To find the concentration of Na in this solution, we need to convert milligrams to grams and then to moles.
- There are 14.7 mg = 0.0147 g of Na in 1 mL of solution.
- The molar mass of Na is 22.99 g/mol, so 0.0147 g of Na is equal to 0.0147 g / 22.99 g/mol = 0.00064 moles of Na.
- The concentration of Na ions is 0.00064 moles / 0.001 L = 0.64 M Na.
d) All have equal [Na]
- Since the concentration of Na in the solutions above is different, they do not have equal concentrations of Na.
- Therefore, the solution with the highest concentration of Na is option c) A solution having 14.7 mg Na/mL with a concentration of 0.64 M Na.