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For total reaction time of 2.5 s, coefficient of friction 0.35, and design speed of 80 km/h, what is the stopping sight distance on a highway?
  • a)
    127 m
  • b)
    132 m
  • c)
    76 m
  • d)
    56 m
Correct answer is option 'A'. Can you explain this answer?
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For total reaction time of 2.5 s, coefficient of friction 0.35, and de...
Given parameters:
- Total reaction time = 2.5 s
- Coefficient of friction = 0.35
- Design speed = 80 km/h

To find:
- Stopping sight distance on a highway

Formula:
Stopping sight distance = perception distance + braking distance

1. Perception Distance:
Perception distance is the distance a vehicle travels during the driver's reaction time.

Perception distance = Total reaction time x Design speed

= 2.5 s x 80 km/h

= 200 m

2. Braking Distance:
Braking distance is the distance a vehicle travels during the braking process.

Braking distance = (Design speed)^2 / (2 x g x coefficient of friction)

where, g = acceleration due to gravity = 9.81 m/s^2

= (80 km/h)^2 / (2 x 9.81 m/s^2 x 0.35)

= 77.7 m

3. Stopping Sight Distance:
Stopping sight distance is the sum of perception distance and braking distance.

Stopping sight distance = Perception distance + Braking distance

= 200 m + 77.7 m

= 277.7 m

Therefore, the stopping sight distance on a highway is 127 m (option A) is incorrect. The correct answer is 277.7 m.
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For total reaction time of 2.5 s, coefficient of friction 0.35, and design speed of 80 km/h, what is the stopping sight distance on a highway?a)127 mb)132 mc)76 md)56 mCorrect answer is option 'A'. Can you explain this answer?
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