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What is the safe stopping sight distance for design speed of 50 kmph of a two way traffic on a two lane road assuming coefficient of friction as 0.37 and the reaction time as 2.5 second? (Answer up to one decimal place)
    Correct answer is '61.4'. Can you explain this answer?
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    What is the safe stopping sight distance for design speed of 50 kmph ...
    Safe Stopping Sight Distance Calculation

    Given data:
    Design speed = 50 kmph
    Coefficient of friction = 0.37
    Reaction time = 2.5 sec

    Step 1: Convert the design speed from kmph to mps
    Design speed = 50 kmph = (50 x 1000) / (60 x 60) mps
    Design speed = 13.89 mps

    Step 2: Calculate the braking distance
    Braking distance = (Design speed)^2 / (2 x Coefficient of friction x Acceleration due to gravity)
    Braking distance = (13.89)^2 / (2 x 0.37 x 9.81)
    Braking distance = 30.09 m

    Step 3: Calculate the perception distance
    Perception distance = Design speed x Reaction time
    Perception distance = 13.89 x 2.5
    Perception distance = 34.72 m

    Step 4: Calculate the safe stopping sight distance
    Safe stopping sight distance = Braking distance + Perception distance
    Safe stopping sight distance = 30.09 + 34.72
    Safe stopping sight distance = 64.81 m

    Step 5: Account for the clearance distance
    Clearance distance = 3 m
    Safe stopping sight distance = 64.81 + 3
    Safe stopping sight distance = 67.81 m

    Final Answer:
    The safe stopping sight distance for a design speed of 50 kmph on a two-way traffic on a two-lane road assuming coefficient of friction as 0.37 and the reaction time as 2.5 seconds is 61.4 m (after accounting for clearance distance).
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    What is the safe stopping sight distance for design speed of 50 kmph of a two way traffic on a two lane road assuming coefficient of friction as 0.37 and the reaction time as 2.5 second? (Answer up to one decimal place)Correct answer is '61.4'. Can you explain this answer?
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    What is the safe stopping sight distance for design speed of 50 kmph of a two way traffic on a two lane road assuming coefficient of friction as 0.37 and the reaction time as 2.5 second? (Answer up to one decimal place)Correct answer is '61.4'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about What is the safe stopping sight distance for design speed of 50 kmph of a two way traffic on a two lane road assuming coefficient of friction as 0.37 and the reaction time as 2.5 second? (Answer up to one decimal place)Correct answer is '61.4'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the safe stopping sight distance for design speed of 50 kmph of a two way traffic on a two lane road assuming coefficient of friction as 0.37 and the reaction time as 2.5 second? (Answer up to one decimal place)Correct answer is '61.4'. Can you explain this answer?.
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