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Shyam walks 5 km towards East and then turns left and walks 6 km. Again he turns right and walks 9 km. Finally he turns to his right and walks 6 km. How far is he from the starting point?
  • a)
    26 km
  • b)
    21 km
  • c)
    14 km
  • d)
    9 km
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Shyam walks 5 km towards East and then turns left and walks 6 km. Agai...

Required distance
= AE = 5 + 9
= 14 km.
View all questions of this test
Most Upvoted Answer
Shyam walks 5 km towards East and then turns left and walks 6 km. Agai...
Given information:
Shyam walks 5 km towards East and then turns left and walks 6 km. Again he turns right and walks 9 km. Finally, he turns to his right and walks 6 km.

To find:
The distance of Shyam from the starting point.

Solution:
To solve this problem, we can use the concept of directions and distances. Let's analyze the given information step by step.

Step 1:
Shyam walks 5 km towards the East.
- This means Shyam moves 5 km in the East direction.

Step 2:
Shyam turns left and walks 6 km.
- Since Shyam turned left, he is now moving towards the North direction.
- Shyam walks 6 km in the North direction.

Step 3:
Shyam turns right and walks 9 km.
- Since Shyam turned right, he is now moving towards the East direction.
- Shyam walks 9 km in the East direction.

Step 4:
Shyam turns right and walks 6 km.
- Since Shyam turned right, he is now moving towards the South direction.
- Shyam walks 6 km in the South direction.

Calculating the distance:
Now, let's calculate the distance of Shyam from the starting point.

- Shyam initially moved 5 km towards the East.
- Then, he moved 6 km towards the North.
- After that, he moved 9 km towards the East.
- Finally, he moved 6 km towards the South.

To find the distance from the starting point, we need to find the net displacement in the East and North directions.

East direction:
- Shyam initially moved 5 km towards the East.
- Then, he moved 9 km towards the East.
- The net displacement in the East direction is 5 + 9 = 14 km towards the East.

North direction:
- Shyam moved 6 km towards the North.
- Then, he moved 6 km towards the South.
- The net displacement in the North direction is 6 - 6 = 0 km towards the North.

The distance of Shyam from the starting point can be calculated using the Pythagorean theorem.
- Distance = √(East displacement)^2 + (North displacement)^2
- Distance = √(14)^2 + (0)^2
- Distance = √(196)
- Distance = 14 km

Therefore, Shyam is 14 km away from the starting point.

Hence, the correct answer is option C) 14 km.
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Shyam walks 5 km towards East and then turns left and walks 6 km. Again he turns right and walks 9 km. Finally he turns to his right and walks 6 km. How far is he from the starting point?a)26 kmb)21 kmc)14 kmd)9 kmCorrect answer is option 'C'. Can you explain this answer?
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