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Shyam walks 5 km towards East and then turns left and walks 6 km. Again he turns right and walks 9 km. Finally he turns to his right and walks 6 km. How far is he from the starting point?
- a)26 km
- b)21 km
- c)14 km
- d)9 km
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Shyam walks 5 km towards East and then turns left and walks 6 km. Agai...
Required distance = AE
= 5 + 9
= 14 km.
Most Upvoted Answer
Shyam walks 5 km towards East and then turns left and walks 6 km. Agai...
Given information:
- Shyam walks 5 km towards East.
- Shyam then turns left and walks 6 km.
- Shyam then turns right and walks 9 km.
- Shyam finally turns right again and walks 6 km.
To find:
- How far is Shyam from the starting point?
Solution:
To solve this problem, we can use the concept of direction and distance.
Step 1: Initial Position
Shyam starts at a point, which we can consider as the origin (0,0).
Step 2: Walking towards East
Shyam walks 5 km towards the East. Since he is moving in a straight line, we can represent this movement using the x-coordinate. So, his new position is (5,0).
Step 3: Turning left and walking
Shyam turns left and walks 6 km. This means he moves in the negative y-coordinate direction. So, his new position is (5,-6).
Step 4: Turning right and walking
Shyam turns right and walks 9 km. This means he moves in the positive x-coordinate direction. So, his new position is (14,-6).
Step 5: Turning right again and walking
Shyam turns right again and walks 6 km. This means he moves in the positive y-coordinate direction. So, his new position is (14,0).
Step 6: Distance from the starting point
To find the distance from the starting point to Shyam's final position, we can use the distance formula, which is given by:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Using the given coordinates, we can calculate the distance as follows:
Distance = √((14 - 0)^2 + (0 - 0)^2)
Distance = √(14^2 + 0^2)
Distance = √(196 + 0)
Distance = √196
Distance = 14
Therefore, Shyam is 14 km away from the starting point.
Final Answer:
Shyam is 14 km away from the starting point. (Option C)
- Shyam walks 5 km towards East.
- Shyam then turns left and walks 6 km.
- Shyam then turns right and walks 9 km.
- Shyam finally turns right again and walks 6 km.
To find:
- How far is Shyam from the starting point?
Solution:
To solve this problem, we can use the concept of direction and distance.
Step 1: Initial Position
Shyam starts at a point, which we can consider as the origin (0,0).
Step 2: Walking towards East
Shyam walks 5 km towards the East. Since he is moving in a straight line, we can represent this movement using the x-coordinate. So, his new position is (5,0).
Step 3: Turning left and walking
Shyam turns left and walks 6 km. This means he moves in the negative y-coordinate direction. So, his new position is (5,-6).
Step 4: Turning right and walking
Shyam turns right and walks 9 km. This means he moves in the positive x-coordinate direction. So, his new position is (14,-6).
Step 5: Turning right again and walking
Shyam turns right again and walks 6 km. This means he moves in the positive y-coordinate direction. So, his new position is (14,0).
Step 6: Distance from the starting point
To find the distance from the starting point to Shyam's final position, we can use the distance formula, which is given by:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Using the given coordinates, we can calculate the distance as follows:
Distance = √((14 - 0)^2 + (0 - 0)^2)
Distance = √(14^2 + 0^2)
Distance = √(196 + 0)
Distance = √196
Distance = 14
Therefore, Shyam is 14 km away from the starting point.
Final Answer:
Shyam is 14 km away from the starting point. (Option C)
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Shyam walks 5 km towards East and then turns left and walks 6 km. Again he turns right and walks 9 km. Finally he turns to his right and walks 6 km. How far is he from the starting point?a)26 kmb)21 kmc)14 kmd)9 kmCorrect answer is option 'C'. Can you explain this answer?
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