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The slope of the tangent to the curve x=t2+3t−8, y=2t2−2t−5 at the point t = 2 is
- a)7/6
- b)5/6
- c)6/7
- d)1
Correct answer is option 'C'. Can you explain this answer?
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The slope of the tangent to the curvex=t2+3t−8,y=2t2−2t&mi...
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The slope of the tangent to the curvex=t2+3t−8,y=2t2−2t&mi...
To find the slope of the tangent to the curve x = t^2 + 3t, we need to find the derivative of x with respect to t and evaluate it at a specific value of t.
Taking the derivative of x with respect to t:
dx/dt = d/dt(t^2 + 3t)
= 2t + 3
Now, let's evaluate this derivative at a specific value of t. Let's say t = 2:
dx/dt = 2(2) + 3
= 4 + 3
= 7
Therefore, the slope of the tangent to the curve x = t^2 + 3t at t = 2 is 7.
Taking the derivative of x with respect to t:
dx/dt = d/dt(t^2 + 3t)
= 2t + 3
Now, let's evaluate this derivative at a specific value of t. Let's say t = 2:
dx/dt = 2(2) + 3
= 4 + 3
= 7
Therefore, the slope of the tangent to the curve x = t^2 + 3t at t = 2 is 7.
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The slope of the tangent to the curvex=t2+3t−8,y=2t2−2t−5at the point t = 2 isa)7/6b)5/6c)6/7d)1Correct answer is option 'C'. Can you explain this answer?
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