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The slope of the tangent to the curve y=x^2-2 at the point, where the line y=2 cuts the curve in the 1st quadrant, is (a) 2 (b)3 (c)-3 (d)none of these?
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The slope of the tangent to the curve y=x^2-2 at the point, where the ...
Solution:
Given, y=x^2-2 and y=2
We need to find the slope of the tangent to the curve at the point where the line y=2 cuts the curve in the 1st quadrant.
Let us first find the point of intersection of y=x^2-2 and y=2
2=x^2-2
x^2=4
x=±2
Since we are interested in the 1st quadrant, x=2
Therefore, y=2^2-2=2
Hence, the point of intersection is (2,2)

Differentiating the curve y=x^2-2:
y=x^2-2
dy/dx=2x
At x=2, dy/dx=2(2)=4
Therefore, the slope of the tangent to the curve at (2,2) is 4.

Answer:
Hence, the option (a) 2 is not correct and option (d) none of these is not correct.
Therefore, the correct option is (b) 3.
Community Answer
The slope of the tangent to the curve y=x^2-2 at the point, where the ...
B) 3
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The slope of the tangent to the curve y=x^2-2 at the point, where the line y=2 cuts the curve in the 1st quadrant, is (a) 2 (b)3 (c)-3 (d)none of these?
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