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The r.m.s. value of a sine wave is 100 A. Its peak value is
- a)70.7 A
- b)141.4 A
- c)150 A
- d)282.8 A
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The r.m.s. value of a sine wave is 100 A. Its peak value isa)70.7 Ab)1...
We have rms value given by,
where, Vm is a peak value.
Thus, we have
Hence,
where, Vm is a peak value.
Thus, we have
Hence,
Most Upvoted Answer
The r.m.s. value of a sine wave is 100 A. Its peak value isa)70.7 Ab)1...
Given: The r.m.s. value of a sine wave is 100 A.
To find: The peak value of the sine wave.
Solution:
We know that the relationship between the r.m.s. value and peak value of a sine wave is given by:
RMS value = Peak value / √2
Therefore, the peak value of the sine wave can be calculated as:
Peak value = RMS value x √2
Substituting the given value of r.m.s. value in the above equation, we get:
Peak value = 100 A x √2
Peak value = 100 A x 1.414
Peak value = 141.4 A
Therefore, the peak value of the sine wave is 141.4 A.
Hence, option (B) is the correct answer.
Note: The factor √2 arises because the r.m.s. value is the equivalent DC value of the AC waveform and the peak value is the highest value attained by the waveform. The ratio of the r.m.s. value to the peak value is constant for a sine wave and is equal to the reciprocal of the square root of 2.
To find: The peak value of the sine wave.
Solution:
We know that the relationship between the r.m.s. value and peak value of a sine wave is given by:
RMS value = Peak value / √2
Therefore, the peak value of the sine wave can be calculated as:
Peak value = RMS value x √2
Substituting the given value of r.m.s. value in the above equation, we get:
Peak value = 100 A x √2
Peak value = 100 A x 1.414
Peak value = 141.4 A
Therefore, the peak value of the sine wave is 141.4 A.
Hence, option (B) is the correct answer.
Note: The factor √2 arises because the r.m.s. value is the equivalent DC value of the AC waveform and the peak value is the highest value attained by the waveform. The ratio of the r.m.s. value to the peak value is constant for a sine wave and is equal to the reciprocal of the square root of 2.
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The r.m.s. value of a sine wave is 100 A. Its peak value isa)70.7 Ab)141.4 Ac)150 Ad)282.8 ACorrect answer is option 'B'. Can you explain this answer?
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