Chemistry Exam > Chemistry Questions > The correct order of M – C (M = Ti, V, ...
Start Learning for Free
The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)
- a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–
- b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+
- c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–
- d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The correct order of M – C (M = Ti, V, Cr and Mn) bond stretchin...
Bond Stretching Frequencies of M C (M = Ti, V, Cr and Mn) Compounds
The correct order of bond stretching frequency of M C (M = Ti, V, Cr and Mn) compounds is given by the increasing order of their atomic numbers. The atomic number of Ti, V, Cr and Mn are 22, 23, 24 and 25 respectively.
Order of Bond Stretching Frequencies
The correct order of bond stretching frequencies is as follows:
[Mn(CO)6] < cr(co)6="" />< [v(co)6]="" />< />
Explanation
The bond stretching frequency is directly proportional to the force constant of the bond and inversely proportional to the reduced mass of the bond. The force constant is related to the strength of the bond and the reduced mass is related to the masses of the two atoms involved in the bond.
In the given compounds, the central metal atom (M) is bonded with six carbon monoxide (CO) ligands. The bond strength and the bond length depend on the nature and size of the central metal atom.
As we move from Mn to Ti, the atomic number and the size of the central metal atom decreases. This leads to stronger and shorter metal-carbon bonds, which in turn results in higher bond stretching frequencies.
Hence, the correct order of bond stretching frequencies is [Mn(CO)6] < cr(co)6="" />< [v(co)6]="" />< [ti(co)6]2,="" which="" is="" option="" c.="" [ti(co)6]2,="" which="" is="" option="" />
The correct order of bond stretching frequency of M C (M = Ti, V, Cr and Mn) compounds is given by the increasing order of their atomic numbers. The atomic number of Ti, V, Cr and Mn are 22, 23, 24 and 25 respectively.
Order of Bond Stretching Frequencies
The correct order of bond stretching frequencies is as follows:
[Mn(CO)6] < cr(co)6="" />< [v(co)6]="" />< />
Explanation
The bond stretching frequency is directly proportional to the force constant of the bond and inversely proportional to the reduced mass of the bond. The force constant is related to the strength of the bond and the reduced mass is related to the masses of the two atoms involved in the bond.
In the given compounds, the central metal atom (M) is bonded with six carbon monoxide (CO) ligands. The bond strength and the bond length depend on the nature and size of the central metal atom.
As we move from Mn to Ti, the atomic number and the size of the central metal atom decreases. This leads to stronger and shorter metal-carbon bonds, which in turn results in higher bond stretching frequencies.
Hence, the correct order of bond stretching frequencies is [Mn(CO)6] < cr(co)6="" />< [v(co)6]="" />< [ti(co)6]2,="" which="" is="" option="" c.="" [ti(co)6]2,="" which="" is="" option="" />
Free Test
FREE
| Start Free Test |
Community Answer
The correct order of M – C (M = Ti, V, Cr and Mn) bond stretchin...
With increasing negative charge electron density increase on metal atom thus metal to carbon back donation increases, with increasing back donation metal carbon bond will be more stronger so m-c stretching frequency increases
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer?
Question Description
The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer?.
The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer?.
Solutions for The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer?, a detailed solution for The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The correct order of M – C (M = Ti, V, Cr and Mn) bond stretching frequency is: (Given : Atomic number of Ti = 22, V = 23, Cr = 24 and Mn = 25)a)[V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+ < [Ti(CO)6]2–b)[Ti(CO)6]2– < [V(CO)6]– < Cr(CO)6 < [Mn(CO)6]+c)[Mn(CO)6]+ < Cr(CO)6 < [V(CO)6]– < [Ti(CO)6]2–d)[Mn(CO)6]+ < [V(CO)6]– < Cr(CO)6 < [Ti(CO)6]2–Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup