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Select the correct  statement regarding [Ph3MeP][AI(BH4)4]
(I) At 298 anion show one signal in 1H NMR
(II) At 298 anion show two signal in 1H NMR
(III) At 298 a quintet is observed in 11B NMR
(IV) At 298 a triplet of triplet is observed in 11B NMR
  • a)
    I and III
  • b)
    I and IV
  • c)
    II and IV
  • d)
    II and III
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Select the correct statement regarding [Ph3MeP][AI(BH4)4](I) At 298 an...
Structure of [AI(BH4)4]-

At 298 terminal and bridging hydrogens are involved in dynamic process. Hence, one signal in 1H NMR. 11B NMR will be a quintet regarding 4 equivalent H.
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Most Upvoted Answer
Select the correct statement regarding [Ph3MeP][AI(BH4)4](I) At 298 an...
Explanation:

In order to determine the correct statement regarding [Ph3MeP][AI(BH4)4](I), we need to analyze the information given for each option.

I. At 298 anion show one signal in 1H NMR:
This statement suggests that the anion [AI(BH4)4]- would exhibit a single signal in the 1H NMR spectrum at 298 K. This implies that all the protons in the molecule are chemically equivalent and experience the same environment.

III. At 298 a quintet is observed in 11B NMR:
This statement suggests that a quintet pattern is observed in the 11B NMR spectrum at 298 K. A quintet pattern indicates the presence of four equivalent neighboring nuclei, which cause the splitting of the central boron signal into five peaks. This implies that the [AI(BH4)4]- anion has four equivalent BH4 groups.

Now, let's consider each statement individually:

I. At 298 anion show one signal in 1H NMR:
This statement is correct because the [AI(BH4)4]- anion has a tetrahedral structure. In a tetrahedral molecule, all the protons are chemically equivalent, and therefore, a single signal is observed in the 1H NMR spectrum.

III. At 298 a quintet is observed in 11B NMR:
This statement is incorrect because the [AI(BH4)4]- anion does not have any boron atoms. It is the [Ph3MeP]+ cation that contains phosphorus atoms. Therefore, we cannot observe a quintet pattern in the 11B NMR spectrum.

Based on the analysis of each statement, it can be concluded that the correct statement regarding [Ph3MeP][AI(BH4)4](I) is:

a) I and III
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Select the correct statement regarding [Ph3MeP][AI(BH4)4](I) At 298 anion show one signal in1H NMR(II) At 298 anion show two signal in1H NMR(III) At 298 a quintet is observed in11B NMR(IV) At 298 a triplet of triplet is observed in11B NMRa)I and IIIb)I and IVc)II and IVd)II and IIICorrect answer is option 'A'. Can you explain this answer?
Question Description
Select the correct statement regarding [Ph3MeP][AI(BH4)4](I) At 298 anion show one signal in1H NMR(II) At 298 anion show two signal in1H NMR(III) At 298 a quintet is observed in11B NMR(IV) At 298 a triplet of triplet is observed in11B NMRa)I and IIIb)I and IVc)II and IVd)II and IIICorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Select the correct statement regarding [Ph3MeP][AI(BH4)4](I) At 298 anion show one signal in1H NMR(II) At 298 anion show two signal in1H NMR(III) At 298 a quintet is observed in11B NMR(IV) At 298 a triplet of triplet is observed in11B NMRa)I and IIIb)I and IVc)II and IVd)II and IIICorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Select the correct statement regarding [Ph3MeP][AI(BH4)4](I) At 298 anion show one signal in1H NMR(II) At 298 anion show two signal in1H NMR(III) At 298 a quintet is observed in11B NMR(IV) At 298 a triplet of triplet is observed in11B NMRa)I and IIIb)I and IVc)II and IVd)II and IIICorrect answer is option 'A'. Can you explain this answer?.
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