Select the correct statement regarding [Ph3MeP][AI(BH4)4](I) At 298 an...
Structure of [AI(BH
4)
4]
-At 298 terminal and bridging hydrogens are involved in dynamic process. Hence, one signal in
1H NMR.
11B NMR will be a quintet regarding 4 equivalent H.
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Select the correct statement regarding [Ph3MeP][AI(BH4)4](I) At 298 an...
Explanation:
In order to determine the correct statement regarding [Ph3MeP][AI(BH4)4](I), we need to analyze the information given for each option.
I. At 298 anion show one signal in 1H NMR:
This statement suggests that the anion [AI(BH4)4]- would exhibit a single signal in the 1H NMR spectrum at 298 K. This implies that all the protons in the molecule are chemically equivalent and experience the same environment.
III. At 298 a quintet is observed in 11B NMR:
This statement suggests that a quintet pattern is observed in the 11B NMR spectrum at 298 K. A quintet pattern indicates the presence of four equivalent neighboring nuclei, which cause the splitting of the central boron signal into five peaks. This implies that the [AI(BH4)4]- anion has four equivalent BH4 groups.
Now, let's consider each statement individually:
I. At 298 anion show one signal in 1H NMR:
This statement is correct because the [AI(BH4)4]- anion has a tetrahedral structure. In a tetrahedral molecule, all the protons are chemically equivalent, and therefore, a single signal is observed in the 1H NMR spectrum.
III. At 298 a quintet is observed in 11B NMR:
This statement is incorrect because the [AI(BH4)4]- anion does not have any boron atoms. It is the [Ph3MeP]+ cation that contains phosphorus atoms. Therefore, we cannot observe a quintet pattern in the 11B NMR spectrum.
Based on the analysis of each statement, it can be concluded that the correct statement regarding [Ph3MeP][AI(BH4)4](I) is:
a) I and III