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If the microprocessor has 10 address lines, then the number of memory locations it is able to address is
  • a)
    512
  • b)
    1024
  • c)
    2048
  • d)
    none
Correct answer is option 'B'. Can you explain this answer?
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If the microprocessor has 10 address lines, then the number of memory ...
Since for n address lines, the number of memory locations able to address is 2^n.
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If the microprocessor has 10 address lines, then the number of memory ...
To understand why the correct answer is option 'B' (1024), let's break down the given information and the concept of address lines and memory locations.

Address Lines:
Address lines are used by the microprocessor to specify the memory location it wants to access. Each address line represents a binary value (0 or 1). The number of address lines determines the maximum number of unique addresses that can be generated by the microprocessor.

Memory Locations:
Memory locations are the individual storage units in the memory. Each memory location can store a certain amount of data, typically measured in bits or bytes.

Calculation:
In this case, the microprocessor has 10 address lines. The number of memory locations it can address can be calculated using the formula 2^n, where n is the number of address lines.

2^10 = 1024

Explanation:
When there are 10 address lines, each line can have two possible values (0 or 1). Therefore, with 10 address lines, the microprocessor can generate 2^10 = 1024 unique addresses. Each of these addresses corresponds to a memory location.

So, the correct answer is option 'B' (1024) because the microprocessor with 10 address lines can address 1024 memory locations.
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A processor uses 2-level page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both 32 bits wide. The memory is byte addressable. For virtual to physical address translation, the 10 most significant bits of the virtual address are used as index into the first level page table while the next 10 bits are used as index into the second level page table. The 12 least significant bits of the virtual address are used as offset within the page. Assume that the page table entries in both levels of page tables are 4 bytes wide. Further, the processor has a translation look-aside buffer (TLB), with a hit rate of 96%. The TLB caches recently used virtual page numbers and the corresponding physical page numbers. The processor also has a physically addressed cache with a hit rate of 90%. Main memory access time is 10 ns, cache access time is 1 ns, and TLB access time is also 1 ns. Assuming that no page faults occur, the average time taken to access a virtual address is approximately (to the nearest 0.5 ns)

A processor uses 2-level page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both 32 bits wide. The memory is byte addressable. For virtual to physical address translation, the 10 most significant bits of the virtual address are used as index into the first level page table while the next 10 bits are used as index into the second level page table. The 12 least significant bits of the virtual address are used as offset within the page. Assume that the page table entries in both levels of page tables are 4 bytes wide. Further, the processor has a translation look-aside buffer (TLB), with a hit rate of 96%. The TLB caches recently used virtual page numbers and the corresponding physical page numbers. The processor also has a physically addressed cache with a hit rate of 90%. Main memory access time is 10 ns, cache access time is 1 ns, and TLB access time is also 1 ns. Assuming that no page faults occur, the average time taken to access a virtual address is approximately (to the nearest 0.5 ns)

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If the microprocessor has 10 address lines, then the number of memory locations it is able to address isa)512b)1024c)2048d)noneCorrect answer is option 'B'. Can you explain this answer?
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