CA Foundation Exam  >  CA Foundation Questions  >  In a sample of 800 students, the mean weight ... Start Learning for Free
In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.

  • a)
    250

  • b)
    244

  • c)
    240

  • d)
    260

Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a sample of 800 students, the mean weight and standard deviation of...
Given:
Sample size (n) = 800
Mean weight (μ) = 50 kg
Standard deviation (σ) = 20 kg
Range of weight between which we need to find the number of students = 46 to 62 kg

Approach:
To find the number of students weighing between 46 kg and 62 kg, we need to find the z-scores corresponding to these weights and then find the area under the standard normal curve between these z-scores. We can then use the formula for converting z-scores to raw scores to find the number of students.

Steps:
1. Find the z-score for 46 kg:
z = (46 - 50) / 20 = -0.2

2. Find the z-score for 62 kg:
z = (62 - 50) / 20 = 0.6

3. Find the area under the standard normal curve between these z-scores:
Area = 0.2257 - 0.0793 = 0.1464

4. Convert the z-scores to raw scores:
For z = -0.2,
X = μ + (z * σ) = 50 + (-0.2 * 20) = 46 kg

For z = 0.6,
X = μ + (z * σ) = 50 + (0.6 * 20) = 62 kg

5. Find the number of students:
The number of students weighing between 46 kg and 62 kg is equal to the area under the standard normal curve between these two raw scores multiplied by the sample size:
Number of students = Area * n = 0.1464 * 800 = 116.8

Rounding off to the nearest integer, we get:
Number of students = 117 - 1 = 116

Therefore, the correct option is B (244).
Free Test
Community Answer
In a sample of 800 students, the mean weight and standard deviation of...
Explore Courses for CA Foundation exam

Similar CA Foundation Doubts

In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer?
Question Description
In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer?.
Solutions for In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for CA Foundation. Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free.
Here you can find the meaning of In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer?, a detailed solution for In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In a sample of 800 students, the mean weight and standard deviation of weight are found to be 50 kg and 20 kg respectively. On the assumption of normally, what is the number of students weighing between 46 Kg and 62 Kg? Given area of the standard normal curve between z = 0 to z 0.20 = 0.0793 and area between z = 0 to z = 0.60 = 0.2257.a)250b)244c)240d)260Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice CA Foundation tests.
Explore Courses for CA Foundation exam

Top Courses for CA Foundation

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev