To calculate the required amounts of 12 M NaOH and 2 M NaOH to make 2 L of 9 M NaOH solution, we will use the formula:

C1V1 + C2V2 = C3V3

where C1 and V1 are the concentration and volume of the first solution, C2 and V2 are the concentration and volume of the second solution, and C3 and V3 are the concentration and volume of the final solution.



To make 2 L of 9 M NaOH solution, we need:

9 M x 2 L = 18 moles of NaOH



Let's assume that x liters of 12 M NaOH are required. We can use the formula above to solve for x:

12 M x + 2 M (2 L - x) = 9 M x 2 L

Simplifying the equation, we get:

10x = 18

x = 1.8 L

Therefore, we need 1.8 L of 12 M NaOH to make 2 L of 9 M NaOH solution.



To calculate the amount of 2 M NaOH required, we can subtract the amount of 12 M NaOH from the total volume of the final solution:

2 L - 1.8 L = 0.2 L

Therefore, we need 0.2 L of 2 M NaOH to make 2 L of 9 M NaOH solution.



To make 2 L of 9 M NaOH solution, we need to mix 1.8 L of 12 M NaOH and 0.2 L of 2 M NaOH.