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The atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.
The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.
The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.
Q.
The metal with high melting point in 3d series is
- a)Cu
- b)Zn
- c)Cr
- d)Fe
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
PassageThe atomic and ionic radii for transition elements are smaller ...
The high melting point of Cr metal is attributed to the involvement of greater number of electrons from (n - 1) d in addition to ns electrons in the interatomic metallic bonding.
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PassageThe atomic and ionic radii for transition elements are smaller ...
Explanation:
The melting point of a metal is influenced by several factors, including the strength of metallic bonding, the number of valence electrons, and the size of the metal atoms.
1. Strength of Metallic Bonding:
The strength of metallic bonding is determined by the number of valence electrons and the effective nuclear charge experienced by these electrons. Transition metals have a high effective nuclear charge due to their partially filled d-orbitals, which leads to stronger metallic bonding and higher melting points compared to s-block elements.
2. Number of Valence Electrons:
The number of valence electrons in a metal affects its melting point. Transition metals generally have more valence electrons than s-block elements, which leads to stronger metallic bonding and higher melting points.
3. Size of Metal Atoms:
The size of metal atoms also plays a role in determining the melting point. Generally, smaller atoms have stronger metallic bonding and higher melting points. The atomic and ionic radii of transition elements are smaller than their corresponding s-block elements due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period. However, the atomic and ionic radii of transition elements show a decreasing trend for the first few elements, remain relatively constant in the middle, and slightly increase towards the end of a given series.
Conclusion:
Among the options provided, chromium (Cr) is the metal with the highest melting point in the 3d series. This is because chromium has a higher effective nuclear charge and a smaller atomic and ionic radius compared to the other elements in the series. The combination of these factors results in stronger metallic bonding and a higher melting point for chromium.
The melting point of a metal is influenced by several factors, including the strength of metallic bonding, the number of valence electrons, and the size of the metal atoms.
1. Strength of Metallic Bonding:
The strength of metallic bonding is determined by the number of valence electrons and the effective nuclear charge experienced by these electrons. Transition metals have a high effective nuclear charge due to their partially filled d-orbitals, which leads to stronger metallic bonding and higher melting points compared to s-block elements.
2. Number of Valence Electrons:
The number of valence electrons in a metal affects its melting point. Transition metals generally have more valence electrons than s-block elements, which leads to stronger metallic bonding and higher melting points.
3. Size of Metal Atoms:
The size of metal atoms also plays a role in determining the melting point. Generally, smaller atoms have stronger metallic bonding and higher melting points. The atomic and ionic radii of transition elements are smaller than their corresponding s-block elements due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period. However, the atomic and ionic radii of transition elements show a decreasing trend for the first few elements, remain relatively constant in the middle, and slightly increase towards the end of a given series.
Conclusion:
Among the options provided, chromium (Cr) is the metal with the highest melting point in the 3d series. This is because chromium has a higher effective nuclear charge and a smaller atomic and ionic radius compared to the other elements in the series. The combination of these factors results in stronger metallic bonding and a higher melting point for chromium.
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PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer?
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PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer?.
PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer?.
Solutions for PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice PassageThe atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.Q.The metal with high melting point in 3d series isa)Cub)Znc)Crd)FeCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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