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Company wishes top simultaneously promotes three of its 8 department assistant mangers. In how many ways these promotions can take place?
Most Upvoted Answer
Company wishes top simultaneously promotes three of its 8 department a...
Solution:

Number of ways to promote three assistant managers out of eight can be calculated using the combination formula.

Formula:

nCr = n! / r! * (n-r)!

where n = total number of items, r = number of items to be selected

Calculation:

n = 8, r = 3

Number of ways = 8C3

= 8! / 3! * (8-3)!

= 8! / 3! * 5!

= (8*7*6) / (3*2*1)

= 56

Therefore, there are 56 ways to promote three assistant managers out of eight.

Explanation:

To understand the solution, we can break down the process into the following steps:

Step 1: Identify the total number of items (n) and the number of items to be selected (r).

In this problem, there are 8 assistant managers and we need to select 3 out of them.

Step 2: Apply the combination formula to calculate the number of ways to select r items from n items.

In this problem, we use the combination formula nCr = n! / r! * (n-r)! to calculate the number of ways to promote three assistant managers out of eight.

Step 3: Simplify the formula and calculate the answer.

We simplify the formula using factorials and calculate the answer to be 56.

Therefore, there are 56 ways to promote three assistant managers out of eight.
Community Answer
Company wishes top simultaneously promotes three of its 8 department a...
These promotions can take place in 56 ways.As we need to select 3 managers out of the 8 managers for promoting to higher posts.So here we will use combinations as order of arrangement is not important as any three can be selected. So we will write 8×7×6/3×2×1=56.
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Company wishes top simultaneously promotes three of its 8 department assistant mangers. In how many ways these promotions can take place?
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