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A Company wishes top simultaneously promotes three of its 8 department assistant mangers. In how many ways these promotions can take place?
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A Company wishes top simultaneously promotes three of its 8 department...
Promoting Department Assistant Managers


There are 8 department assistant managers in a company and the company wishes to simultaneously promote three of them. Let's calculate the number of ways these promotions can take place.


Formula

The formula to calculate the number of ways to select 'r' items from a group of 'n' items is:

nCr = n! / (r! * (n-r)!)


Calculation

In this case, we need to select 3 assistant managers from a group of 8, so:

8C3 = 8! / (3! * (8-3)!) = (8 * 7 * 6) / (3 * 2 * 1) = 56


Explanation

There are 56 ways to simultaneously promote three assistant managers from a group of 8. This means that there are 56 different combinations of three people that can be selected from the group of 8.


Conclusion

The company can promote three of its 8 department assistant managers in 56 different ways. This calculation is based on the formula to calculate the number of ways to select 'r' items from a group of 'n' items.
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A Company wishes top simultaneously promotes three of its 8 department assistant mangers. In how many ways these promotions can take place?
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A Company wishes top simultaneously promotes three of its 8 department assistant mangers. In how many ways these promotions can take place? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about A Company wishes top simultaneously promotes three of its 8 department assistant mangers. In how many ways these promotions can take place? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Company wishes top simultaneously promotes three of its 8 department assistant mangers. In how many ways these promotions can take place?.
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