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CsBr crystallises in a BCC lattice with lattice parameter of 4.29 Å. The angle at which the second order reflection maxima may be expected from (111) planes (when X-rays of wavelength 0.50Å are used) is ______Å. (upto two decimal places)
    Correct answer is between '11.60,11.70'. Can you explain this answer?
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    CsBr crystallises in a BCC lattice with lattice parameter of 4.29&Arin...

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    CsBr crystallises in a BCC lattice with lattice parameter of 4.29&Arin...
    The lattice parameter of a crystal refers to the distance between the lattice points in the crystal lattice. For CsBr, it crystallizes in a Body-Centered Cubic (BCC) lattice structure.

    In a BCC lattice, the lattice parameter (a) can be related to the atomic radius (r) of the atoms in the crystal using the formula:

    a = 4√(2) * r

    Given that the lattice parameter (a) for CsBr is 4.29, we can rearrange the formula to solve for the atomic radius (r):

    r = a / (4√(2))

    Plugging in the value of a = 4.29 into the equation, we get:

    r = 4.29 / (4√(2))

    r ≈ 1.21 Å (angstroms)

    Therefore, the atomic radius of CsBr in this BCC lattice structure is approximately 1.21 Å.
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    CsBr crystallises in a BCC lattice with lattice parameter of 4.29Å. The angle at which the second order reflection maxima may be expected from (111) planes (when X-rays of wavelength 0.50Å are used) is ______Å. (upto two decimal places)Correct answer is between '11.60,11.70'. Can you explain this answer?
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