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In germanium semiconductor at T 300 K, the acceptor concentrations is Na 1013 cm3 and donor concentration is Nd 0. The thermal equilibrium concentration p0 is
- a)2.97 x 109 cm3
- b)2.68 x 1012 cm3
- c)2.95 x 1013 cm3
- d)2.4 cm3
Correct answer is option 'C'. Can you explain this answer?
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Calculation of Thermal Equilibrium Concentration p0 in Germanium Semiconductor
Given data:
Acceptor concentration, Na = 1013 cm-3
Donor concentration, Nd = 0
Temperature, T = 300 K
Formula used to calculate thermal equilibrium concentration p0:
p0 = (ni^2)/Na
Where ni is the intrinsic carrier concentration and is given by:
ni^2 = (pi)(ni)
Where pi is the hole concentration and ni is the electron concentration.
Calculation of ni:
ni^2 = (pi)(ni)
At thermal equilibrium, pi = Nd = 0
Therefore, ni^2 = (Nd + Na)(ni)
ni^2 = (1013)(2.25 x 1019)
ni = 6.23 x 109 cm-3
Calculation of p0:
p0 = (ni^2)/Na
p0 = (6.23 x 109)2/1013
p0 = 2.95 x 1013 cm-3
Therefore, the correct answer is option C, which is 2.95 x 1013 cm-3.
Given data:
Acceptor concentration, Na = 1013 cm-3
Donor concentration, Nd = 0
Temperature, T = 300 K
Formula used to calculate thermal equilibrium concentration p0:
p0 = (ni^2)/Na
Where ni is the intrinsic carrier concentration and is given by:
ni^2 = (pi)(ni)
Where pi is the hole concentration and ni is the electron concentration.
Calculation of ni:
ni^2 = (pi)(ni)
At thermal equilibrium, pi = Nd = 0
Therefore, ni^2 = (Nd + Na)(ni)
ni^2 = (1013)(2.25 x 1019)
ni = 6.23 x 109 cm-3
Calculation of p0:
p0 = (ni^2)/Na
p0 = (6.23 x 109)2/1013
p0 = 2.95 x 1013 cm-3
Therefore, the correct answer is option C, which is 2.95 x 1013 cm-3.
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In germanium semiconductor at T 300 K, the acceptor concentrations is Na 1013 cm3 and donor concentration is Nd 0. The thermal equilibrium concentration p0 isa)2.97 x 109cm3b)2.68 x 1012cm3c)2.95 x 1013cm3d)2.4 cm3Correct answer is option 'C'. Can you explain this answer?
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In germanium semiconductor at T 300 K, the acceptor concentrations is Na 1013 cm3 and donor concentration is Nd 0. The thermal equilibrium concentration p0 isa)2.97 x 109cm3b)2.68 x 1012cm3c)2.95 x 1013cm3d)2.4 cm3Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In germanium semiconductor at T 300 K, the acceptor concentrations is Na 1013 cm3 and donor concentration is Nd 0. The thermal equilibrium concentration p0 isa)2.97 x 109cm3b)2.68 x 1012cm3c)2.95 x 1013cm3d)2.4 cm3Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In germanium semiconductor at T 300 K, the acceptor concentrations is Na 1013 cm3 and donor concentration is Nd 0. The thermal equilibrium concentration p0 isa)2.97 x 109cm3b)2.68 x 1012cm3c)2.95 x 1013cm3d)2.4 cm3Correct answer is option 'C'. Can you explain this answer?.
In germanium semiconductor at T 300 K, the acceptor concentrations is Na 1013 cm3 and donor concentration is Nd 0. The thermal equilibrium concentration p0 isa)2.97 x 109cm3b)2.68 x 1012cm3c)2.95 x 1013cm3d)2.4 cm3Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In germanium semiconductor at T 300 K, the acceptor concentrations is Na 1013 cm3 and donor concentration is Nd 0. The thermal equilibrium concentration p0 isa)2.97 x 109cm3b)2.68 x 1012cm3c)2.95 x 1013cm3d)2.4 cm3Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In germanium semiconductor at T 300 K, the acceptor concentrations is Na 1013 cm3 and donor concentration is Nd 0. The thermal equilibrium concentration p0 isa)2.97 x 109cm3b)2.68 x 1012cm3c)2.95 x 1013cm3d)2.4 cm3Correct answer is option 'C'. Can you explain this answer?.
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