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At 298,  for the reaction:

Cp,m = 8.53, 33.58, 29.12 and 28.82 jK-1mol-1 for graphite, H2O(g), CO(g) and H2(g) respectively. Calculate  and asume heat capacities are assume heat capacities are independent of temperature?
  • a)
    102.80kJ/mol
  • b)
    198.60kJ/mol
  • c)
    132.86 J/mol
  • d)
    -119.6 kJ/mol
Correct answer is option 'C'. Can you explain this answer?
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At 298,for the reaction:Cp,m = 8.53, 33.58, 29.12 and 28.82 jK-1mol-1 ...

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At 298,for the reaction:Cp,m = 8.53, 33.58, 29.12 and 28.82 jK-1mol-1 for graphite, H2O(g), CO(g) and H2(g) respectively. Calculateand asume heat capacities are assume heat capacities are independent of temperature?a)102.80kJ/molb)198.60kJ/molc)132.86 J/mold)-119.6kJ/molCorrect answer is option 'C'. Can you explain this answer?
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At 298,for the reaction:Cp,m = 8.53, 33.58, 29.12 and 28.82 jK-1mol-1 for graphite, H2O(g), CO(g) and H2(g) respectively. Calculateand asume heat capacities are assume heat capacities are independent of temperature?a)102.80kJ/molb)198.60kJ/molc)132.86 J/mold)-119.6kJ/molCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about At 298,for the reaction:Cp,m = 8.53, 33.58, 29.12 and 28.82 jK-1mol-1 for graphite, H2O(g), CO(g) and H2(g) respectively. Calculateand asume heat capacities are assume heat capacities are independent of temperature?a)102.80kJ/molb)198.60kJ/molc)132.86 J/mold)-119.6kJ/molCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 298,for the reaction:Cp,m = 8.53, 33.58, 29.12 and 28.82 jK-1mol-1 for graphite, H2O(g), CO(g) and H2(g) respectively. Calculateand asume heat capacities are assume heat capacities are independent of temperature?a)102.80kJ/molb)198.60kJ/molc)132.86 J/mold)-119.6kJ/molCorrect answer is option 'C'. Can you explain this answer?.
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