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Which of the following complex exhibits geometrical isomerism:
  • a)
    [Zn(gly)2]
  • b)
    [Cu(en)(NH3)2]+
  • c)
    [PtBrCl(NH3)(py)] 
  • d)
    [Ni(CN)2(CO)2]2-
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Which of the following complex exhibits geometrical isomerism:a)[Zn(gl...
[PtBrCl NH3 Py] Pt2+ is dsp2 hybridised & hence geometry is square planner & sq. planner complex with four different ligands shows geometrical isomerism.
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Most Upvoted Answer
Which of the following complex exhibits geometrical isomerism:a)[Zn(gl...
Complexes that exhibit geometrical isomerism have different spatial arrangements of ligands around the central metal atom. Geometrical isomerism occurs when there are different possible arrangements of ligands that cannot be interconverted by rotation around a single bond.

In the given options, the complex [PtBrCl(NH3)(py)] exhibits geometrical isomerism. Let's break down the complex and analyze its structure.

Complex: [PtBrCl(NH3)(py)]
The central metal atom in this complex is platinum (Pt). It is coordinated to four ligands: bromine (Br), chlorine (Cl), ammonia (NH3), and pyridine (py).

Identifying Ligands:
- Br: Bromine
- Cl: Chlorine
- NH3: Ammonia
- py: Pyridine

Geometry:
The geometry of the complex can be determined by considering the electronic and steric effects of the ligands. In this case, the Pt atom is surrounded by four different ligands, which leads to the possibility of geometrical isomerism.

Geometrical Isomerism in [PtBrCl(NH3)(py)]:
The geometrical isomerism in this complex arises due to the presence of two different ligands, NH3 and py, which are both monodentate ligands. These ligands can occupy either a cis or trans position with respect to each other.

Cis-Isomer:
In the cis-isomer, the NH3 and py ligands are on the same side of the Pt atom. This arrangement is represented as [PtBrCl(NH3)(py)](cis).

Trans-Isomer:
In the trans-isomer, the NH3 and py ligands are on opposite sides of the Pt atom. This arrangement is represented as [PtBrCl(py)(NH3)](trans).

Conclusion:
The complex [PtBrCl(NH3)(py)] exhibits geometrical isomerism due to the presence of two different monodentate ligands, NH3 and py. The cis and trans isomers have different arrangements of ligands around the Pt atom and cannot be interconverted by rotation around a single bond.
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