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The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:
- a)[Be(acac)2]
- b)[Ir(H2O)3(NH3) 3]3+
- c)[Cr(en)3]3+
- d)[Rh(H2O)2(en)2] 3+
Correct answer is option 'D'. Can you explain this answer?
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The complex which exhibits cis-trans isomerism as well as can be resol...
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The complex which exhibits cis-trans isomerism as well as can be resol...
Explanation:
Cis-trans isomerism refers to the different arrangements of ligands around a central metal ion. In order for a complex to exhibit cis-trans isomerism, it must have at least two different ligands that can occupy adjacent positions around the metal ion.
The ability to be resolved into d and l forms refers to the presence of chiral ligands in the complex. Chiral ligands are molecules that are non-superimposable on their mirror image. When a complex contains chiral ligands, it can exist in two different forms that are mirror images of each other, known as enantiomers.
Out of the given options, the complex [Rh(H2O)2(en)2]3 satisfies both conditions of cis-trans isomerism and chiral ligands. Here is a detailed explanation:
[Cis-trans isomerism]
The complex has two different ligands, H2O and en (ethylenediamine), which can occupy adjacent positions around the Rh ion.
The H2O ligands can be oriented cis (on the same side) or trans (on opposite sides) to each other, giving rise to two different isomers:
[ Rh(H2O)2(en)2 ]3 -cis
[ Rh(H2O)2(en)2 ]3 -trans
[Chiral ligands]
The en ligands are chiral, as they contain a central carbon atom with four different groups attached to it. Each en ligand can exist in two different forms, known as R and S enantiomers.
Since there are two en ligands in the complex, there are a total of four possible enantiomers:
[ Rh(H2O)2(R,R-en)2 ]3
[ Rh(H2O)2(R,S-en)2 ]3
[ Rh(H2O)2(S,R-en)2 ]3
[ Rh(H2O)2(S,S-en)2 ]3
Overall, the complex [Rh(H2O)2(en)2]3 exhibits both cis-trans isomerism and chiral ligands, making it the correct answer to the given question.
Cis-trans isomerism refers to the different arrangements of ligands around a central metal ion. In order for a complex to exhibit cis-trans isomerism, it must have at least two different ligands that can occupy adjacent positions around the metal ion.
The ability to be resolved into d and l forms refers to the presence of chiral ligands in the complex. Chiral ligands are molecules that are non-superimposable on their mirror image. When a complex contains chiral ligands, it can exist in two different forms that are mirror images of each other, known as enantiomers.
Out of the given options, the complex [Rh(H2O)2(en)2]3 satisfies both conditions of cis-trans isomerism and chiral ligands. Here is a detailed explanation:
[Cis-trans isomerism]
The complex has two different ligands, H2O and en (ethylenediamine), which can occupy adjacent positions around the Rh ion.
The H2O ligands can be oriented cis (on the same side) or trans (on opposite sides) to each other, giving rise to two different isomers:
[ Rh(H2O)2(en)2 ]3 -cis
[ Rh(H2O)2(en)2 ]3 -trans
[Chiral ligands]
The en ligands are chiral, as they contain a central carbon atom with four different groups attached to it. Each en ligand can exist in two different forms, known as R and S enantiomers.
Since there are two en ligands in the complex, there are a total of four possible enantiomers:
[ Rh(H2O)2(R,R-en)2 ]3
[ Rh(H2O)2(R,S-en)2 ]3
[ Rh(H2O)2(S,R-en)2 ]3
[ Rh(H2O)2(S,S-en)2 ]3
Overall, the complex [Rh(H2O)2(en)2]3 exhibits both cis-trans isomerism and chiral ligands, making it the correct answer to the given question.
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The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer?.
The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer?.
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The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The complex which exhibits cis-trans isomerism as well as can be resolved into d and ℓ forms:a)[Be(acac)2]b)[Ir(H2O)3(NH3)3]3+c)[Cr(en)3]3+d)[Rh(H2O)2(en)2]3+Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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