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In an ionic oxide, oxide ions are arranged in hcp array and positive ion occupy two thirds of octahedral void simplest formula of metal M is
  • a)
    M2O6
  • b)
    M4O6
  • c)
    M3O2
  • d)
    M6O4
Correct answer is option 'B'. Can you explain this answer?
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Explanation:

In an ionic oxide, the oxide ions (O2-) are arranged in a hexagonal close-packed (hcp) array. This means that the oxide ions are arranged in a close-packed structure, with each oxide ion surrounded by six other oxide ions in a hexagonal pattern.

The positive ions (M+) occupy two-thirds of the octahedral voids in the hcp array. This means that for every two oxide ions, there will be one M+ ion occupying an octahedral void.

To determine the simplest formula of the metal M, we need to consider the ratio of M+ ions to O2- ions. Since the M+ ions occupy two-thirds of the octahedral voids, the ratio of M+ ions to O2- ions is 2:3.

Calculating the simplest formula:

Let's assume the simplest formula of the metal M is MX.

Since the ratio of M+ ions to O2- ions is 2:3, we can write the formula as M2O3.

However, we need to simplify the formula further.

The formula M2O3 suggests that there are two M+ ions for every three O2- ions. But we know that the M+ ions occupy two-thirds of the octahedral voids, which means that there are only two M+ ions for every two O2- ions.

Therefore, we can simplify the formula to M2O2.

Finally, we simplify the formula further by dividing both subscripts by 2, resulting in the simplest formula M1O1.

Final answer:

The simplest formula of the metal M is MO, which corresponds to option B (M4O6).
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In an ionic oxide, oxide ions are arranged in hcp array and positive ion occupy two thirds of octahedral void simplest formula of metal M isa)M2O6b)M4O6c)M3O2d)M6O4Correct answer is option 'B'. Can you explain this answer?
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