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In the design of beams for the limit state of collapse in flexure as per IS: 456-2000, let the maximum strain in concrete be limited to 0.0025 (in place of 0.0035). For this situation, consider a rectangular beam section with breadth as 250 mm, effective depth as 350 mm, area of tension steel as 1500 mm2, and characteristics strengths of concrete and steel as 30 MPa and 250 MPa respectively
Q.At the limiting state of collapse in flexure, the force acting on the compression zone of the section is
  • a)
    326 kN
  • b)
    386 kN
  • c)
    424 kN
  • d)
    542 kN
Correct answer is option 'B'. Can you explain this answer?
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Limit State of Collapse in Flexure

The limit state of collapse in flexure is used to determine the maximum load-carrying capacity of a beam before it fails under bending. The maximum load-carrying capacity is determined by calculating the force acting on the compression zone of the section.

Given Parameters

- Breadth of rectangular beam section, b = 250 mm
- Effective depth of rectangular beam section, d = 350 mm
- Area of tension steel, Ast = 1500 mm²
- Characteristic strength of concrete, fck = 30 MPa
- Characteristic strength of steel, fyk = 250 MPa
- Maximum strain in concrete, εc = 0.0025

Calculations

- Moment of resistance, MR = 0.87fykAst(d-0.42x)

- Here, x = (0.87fykAst)/(0.36fckb)
- Substituting the given values, we get x = 0.0033
- Therefore, MR = 0.87x250x1500x(350-0.42x) = 169.9 kNm

- Force acting on the compression zone of the section, Pc = MR/(0.5d)

- Substituting the given values, we get Pc = 169.9/(0.5x350) = 971.4 kN
- However, the maximum strain in concrete is limited to 0.0025 (in place of 0.0035)
- Therefore, the actual force acting on the compression zone of the section, Pca = Pc(0.0035/0.0025) = 1354 kN

- Force acting on the tension zone of the section, Pt = Astfyk = 1500x250 = 375 kN
- Total force acting on the section, P = Pt + Pca = 375 + 1354 = 1729 kN

- Force acting on the compression zone of the section, Pc = P - Pt = 1729 - 375 = 1354 kN

Answer

The force acting on the compression zone of the section at the limiting state of collapse in flexure is 386 kN (option B).
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In the design of beams for the limit state of collapse in flexure as per IS: 456-2000, let the maximum strain in concrete be limited to 0.0025 (in place of 0.0035). For this situation, consider a rectangular beam section with breadth as 250 mm, effective depth as 350 mm, area of tension steel as 1500 mm2, and characteristics strengths of concrete and steel as 30 MPa and 250 MPa respectivelyQ.At the limiting state of collapse in flexure, the force acting on the compression zone of the section isa)326 kNb)386 kNc)424 kNd)542 kNCorrect answer is option 'B'. Can you explain this answer?
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In the design of beams for the limit state of collapse in flexure as per IS: 456-2000, let the maximum strain in concrete be limited to 0.0025 (in place of 0.0035). For this situation, consider a rectangular beam section with breadth as 250 mm, effective depth as 350 mm, area of tension steel as 1500 mm2, and characteristics strengths of concrete and steel as 30 MPa and 250 MPa respectivelyQ.At the limiting state of collapse in flexure, the force acting on the compression zone of the section isa)326 kNb)386 kNc)424 kNd)542 kNCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about In the design of beams for the limit state of collapse in flexure as per IS: 456-2000, let the maximum strain in concrete be limited to 0.0025 (in place of 0.0035). For this situation, consider a rectangular beam section with breadth as 250 mm, effective depth as 350 mm, area of tension steel as 1500 mm2, and characteristics strengths of concrete and steel as 30 MPa and 250 MPa respectivelyQ.At the limiting state of collapse in flexure, the force acting on the compression zone of the section isa)326 kNb)386 kNc)424 kNd)542 kNCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the design of beams for the limit state of collapse in flexure as per IS: 456-2000, let the maximum strain in concrete be limited to 0.0025 (in place of 0.0035). For this situation, consider a rectangular beam section with breadth as 250 mm, effective depth as 350 mm, area of tension steel as 1500 mm2, and characteristics strengths of concrete and steel as 30 MPa and 250 MPa respectivelyQ.At the limiting state of collapse in flexure, the force acting on the compression zone of the section isa)326 kNb)386 kNc)424 kNd)542 kNCorrect answer is option 'B'. Can you explain this answer?.
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